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NemiM [27]
3 years ago
11

A spaceship is moving away from Earth at 0.892c when it fires a small rocket in the forward direction at 0.426c relative to the

spaceship. Calculate the rocket's speed relative to Earth (in m/s).
Physics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

The rocket's speed relative to Earth is 2.25\times10^{8}\ m/s.

Explanation:

Given that,

Speed of spaceship = 0.892c

Speed  of rocket = 0.426c

We need to calculate the rocket's speed relative to Earth

Using formula of relative speed

v=\dfrac{v_{s}-v_{r}}{1-(\dfrac{v_{r}v_{s}}{c^2})}

Put the value into the formula

v=\dfrac{0.892c-0.426c}{1-(\dfrac{0.892c\times0.426c}{c^2})}

v=c\dfrac{0.892-0.426}{1-0.379992}

v=c\times0.7516

v=2.25\times10^{8}\ m/s

Hence, The rocket's speed relative to Earth is 2.25\times10^{8}\ m/s.

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