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Vikentia [17]
3 years ago
7

What is the difference between speed and velocity ?

Physics
1 answer:
oee [108]3 years ago
4 0

velocity describes speed with direction.

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A pair of slits in a double slit experiment are illuminated with monochromatic light of wavelength 480 nm. The slits are separat
Romashka-Z-Leto [24]

Using the appropriate approximations:

dx/L = mλ

d = slit separation

x = fringe spacing

L = distance between slits and screen

m = some integer, used to determine the distance from the central bright fringe to another bright fringe


We don't really need a value for m because we're calculating the distance between any pair of consecutive fringes. Let's just set m = 1


Given values:

d = 1.0mm

L = 2.0m

λ = 480nm


Substitute the terms in the equation with our given values and solve for x:

1.0*10⁻³*x/2 = 480*10⁻9

<h3>x = 0.96mm</h3>
8 0
3 years ago
A student pushes a 5 kg box initially at rest along a flat, rough table with a rightward force of 10 N. The frictional force act
Pie

Answer:

Please find attached pdf

Explanation:

Download pdf
8 0
3 years ago
4. Water is flowing at 12m/s in a horizontal pipe under a pressure of 600kpa
shusha [124]

Answer:

a. 192 m/s

b. -17,760 kPa

Explanation:

First let's write the flow rate of the liquid, using the following equation:

Q = A*v

Where Q is the flow rate, A is the cross section area of the pipe (A = pi * radius^2) and v is the speed of the liquid. The flow rate in both parts of the pipe (larger radius and smaller radius) needs to be the same, so we have:

a.

A1*v1 = A2*v2

pi * 0.02^2 * 12 = pi * 0.005^2 * v2

v2 = 0.02^2 * 12 / 0.005^2

v2 = 192 m/s

b.

To find the pressure of the other side, we need to use the Bernoulli equation: (600 kPa = 600000 N/m2)

P1 + d1*v1^2/2 = P2 + d1*v2^2/2

Where d1 is the density of the liquid (for water, we have d1 = 1000 kg/m3)

600000 + 1000*12^2/2 = P2 + 1000*192^2/2

P2 = 600000 + 72000 - 1000*192^2/2

P2 = -17760000 N/m2 = -17,760 kPa

The speed in the smaller part of the pipe is too high, the negative pressure in the second part means that the inicial pressure is not enough to maintain this output speed.

4 0
3 years ago
I need help find how much tension is in the string????
Nikitich [7]

Answer:

When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.

Image result for I need help find how much tension is in the string???? And can you explain how you got it after you get the answer plz????

Hence, in such a case the tension will be equal to the centrifugal force.

Formula for tension = centrifugal force = mv2/r.

So the formula of tension will be = centripetal force – force of gravity = mv2/r – mg = m(v2/r-g)

The formula of tension will be = centripetal force + force of gravity = mv2/r + mg = m(v2/r+g)

Explanation:

5 0
3 years ago
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac
Sedbober [7]

Answer:

v = 1.2 m/s

Explanation:

The wavelength of the waves is given as the horizontal distance between the crests:

λ = wavelength = 5.5 m

Now, the time period is given as the time taken by boat to move from the highest point again to the highest point. So it will be equal to twice the time taken by the boat to travel from highest to the lowest point:

T = Time Period = 2(2.3 s) = 4.6 s

Now, the speed of the wave is given as:

v = f\lambda

where,

v= speed of wave = ?

f = frequency of wave = \frac{1}{T} = \frac{1}{4.6\ s} = 0.217\ Hz

Therefore,

v = (0.217\ Hz)(5.5\ m)\\

<u>v = 1.2 m/s</u>

5 0
3 years ago
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