To solve this problem we will apply the linear motion kinematic equations, which describe the change in velocity, depending on the acceleration and the distance traveled, that is,

Where,
= Final Velocity
= Initial Velocity
a = Acceleration
h = height
Our values are given as,

Replacing we have,



Therefore the height of the cliff is 121ft
Answer:
I do belive that it is B hrs cn I an gn
Answer:
pretty sure its B if it isnt im so so sorry
Explanation:
Answer:
t=2.10 s
u= 47.40 m/s
Explanation:
given that
h= 21.8 m
x= 101 m
g=9.8 m/s²
Lets take horizontal speed of ball = u m/s
The vertical speed of the car at initial condition is zero ( v= 0).
We know that

v= 0 m/s

now by putting the values
21.8 = 1/2 x 9.8 x t²
t=2.10 s
This is time when ball was in motion.
Now in horizontal direction
x = u .t
101 = u x 2.1
u= 47.40 m/s