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Snezhnost [94]
3 years ago
5

According to our theory of solar system formation, why did uranus and neptune end up to be much less massive than jupiter and sa

turn?
Physics
1 answer:
omeli [17]3 years ago
8 0
Particles in the solar nebula were more spread out at greater distances, so that accretion took longer and there was less time to pull in gas before the solar wind cleared the nebula.
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A roundabout in a fairground requires an input power of 2.5 kW when operating at a constant angular velocity of 0.47 rad s–1 . (
natita [175]

Answer:

Explanation:

Since the roundabout is rotating with uniform velocity ,

input power = frictional power

frictional power = 2.5 kW

frictional torque x angular velocity = 2.5 kW

frictional torque x .47 = 2.5 kW

frictional torque = 2.5 / .47 kN .m

= 5.32 kN . m

= 5 kN.m

b )

When power is switched off , it will decelerate because of frictional torque .

5 0
3 years ago
A person observes a firework display for A safe distance of .750 km. Assuming that sound travels at 340 m/s in air what is the t
WINSTONCH [101]

Answer:

t = 2.2 s

Explanation:

Given that,

A person observes a firework display for A safe distance of 0.750 km.

d = 750 m

The speed of sound in air, v = 340 m/s

We need to find the between the person see and hear a firework explosion. let it is t. So, using the formula of speed.

v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{750\ m}{340\ m/s}\\\\t=2.2\ s

So, the required time is 2.2 seconds.

3 0
3 years ago
How quickly do muscles become fatigued?​
agasfer [191]

Answer:

Fatigue is usually defined as the reversible decline of performance during activity, and most recovery occurs within the first hour. However, there is also a slowly reversible component that can take several days to reverse (155). Muscle injury also causes a decline in performance that reverses only very slowly.

5 0
3 years ago
Several types of radiation may be emitted during radioactive decay. The equation represents
Fittoniya [83]
I think the answer is B
5 0
4 years ago
Read 2 more answers
A chamber fitted with a piston contains 1.90 mol of an ideal gas. Part A The piston is slowly moved to decrease the chamber volu
yarga [219]

Answer:

The work done is 5136.88 J.

Explanation:

Given that,

n = 1.90 mol

Temperature = 296 K

If the initial volume is V then the final volume will be V/3.

We need to calculate the work done

Using formula of work done

W=nRT\ ln(\dfrac{V_{f}}{V_{i}})

Put the value into the formula

W=1.90\times8.314\times296\ ln(\dfrac{\dfrac{V}{3}}{V})

W=1.90\times8.314\times296\ ln(\dfrac{1}{3})

W=−5136.88\ J

The Work done on the system.

Hence, The work done is 5136.88 J.

5 0
3 years ago
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