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3 years ago

The equation of the line of best fit of a scatter plot is y = 12x + 7. What is the slope of the equation? −12 −7 12 7

Mathematics

2 answers:

Taya2010 [7]3 years ago

8 0

I would say 12 i think

BabaBlast [244]3 years ago

6 0

Well,

Slope-intercept form is given as follows:
y = mx + b

In this equation, "m" is the slope, and "b" is the y-intercept.

y = 12x + 7

We can clearly see that the 12 in the equation is the "m" in the general slope-intercept form.

Therefore, the slope of the equation is 12.

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Step-by-step explanation:

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3 years ago

The average speed of one airplane is 200 mph faster than that of an automobile. If the automobile starts at 3 a.m. and the airpl

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3 years ago

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Ainat [17]

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3 years ago

For skewed data displays, the median is often a better esitmate of the center of distribution than the mean, but

bazaltina [42]

For skewed data displays, the median is often a better estimate of the center of distribution than the mean because the former is unaffected by large numbers.

Mean refers to the average of set of two or more numbers.

Mean of a set having 'n' numbers = $\frac{Sum Of 'n' Numbers}{n}$

<h3>What is median?</h3>

Median refers to the middle-most value of a list of numbers, arranged either in ascending or descending order.

Median = $\left \{ {{\frac{n}{2}^{th} term, if n = even } \atop( (\frac{n-1}{2}+\frac{n+1}{2})/2)^{th} term, if n = odd }} \right.$

Now,

Since it takes the average of all the values in the data set, the mean is the most widely used measure of central tendency.
Because it is unaffected by exceptionally big numbers, the median performs better than the mean when analyzing data from skewed distributions.

Hence, For skewed data displays, the median is often a better estimate of the center of distribution than the mean.

To learn more about mean and median, refer to the link:brainly.com/question/6281520

#SPJ4

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1 year ago

PLEASE HELPP ♥

kirza4 [7]

Answer:

An exponential function is a function of the form

f(x)=bx

where b≠1 is a positive real number. The domain of an exponential function is (−∞,∞) and the range is (0,∞).

Solve the equation: 52x−3=752x−3=7.

Since we can’t easily rewrite both sides as exponentials with the same base, we’ll use logarithms instead. Above we said that logb(x)=ylogb⁡(x)=y means that by=xby=x. That statement means that each exponential equation has an equivalent logarithmic form and vice-versa. We’ll convert to a logarithmic equation and solve from there.

52x−3log

⎛⎝⎜

⎞⎠⎟=7=2x−352x−3=7log5

⁡(7

)=2x−3

From here, we can solve for xx directly.

2xx=log5(7)+3=log5(7)+32

A logarithmic function is a function defined as follows

logb(x)=ymeans thatby=xlogb⁡(x)=ymeans thatby=x

where b≠1b≠1 is a positive real number. The domain of a logarithmic function is (0,∞)(0,∞) and the range is (−∞,∞)(−∞,∞).

Solve the equation:

log3(2x+1)=1−log3(x+2).log3⁡(2x+1)=1−log3⁡(x+2).

With more than one logarithm, we’ll typically try to use the properties of logarithms to combine them into a single term.

log3(2x+1)log3(2x+1)+log3(x+2)log3((2x+1)(x+2))log3(2x2+5x+2)2x2+5x+22x2+5x−1=1−log3(x+2)=1=1=1=3=0log3⁡(2x+1)=1−log3⁡(x+2)log3⁡(2x+1)+log3⁡(x+2)=1log3⁡((2x+1)(x+2))=1log3⁡(2x2+5x+2)=12x2+5x+2=32x2+5x−1=0

Let’s use quadratic formula to solve this.

x=−5±52−4⋅2⋅−1−−−−−−−−−−−√2⋅2=−5±

−−−−−−−−⎷4.x=−5±52−4⋅2⋅−12⋅2=−5±33

What happens if we try to plug x=

4 0

3 years ago