(-3,0) and (5, -2)
slope = (0 + 2) /(-3 - 5) = -2/8
y - 0 = -2/8 (x + 3)
y = -2/8 x - 6/8
8y = -2x - 6
2x + 8y = - 6
Answer is
D. 2x + 8y = -6
I’m sorry I don’t know how to solve this it’s just that I need points to ask a question
i think this is right, pls let me know if i'm wrong.
12m(squared)+15my
hello :<span>
<span>an equation of the circle Center at the
O(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = AO
r² = (AO)²
r² = (4-0)² +(5-0)² = 16+25=41
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through B(4, 5) is : x² +y² = 41</span></span>
x² +y² - 41=0
