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4 years ago

Please help :) Evaluate the expression: 75+125÷25×5 A.1.6 B. 40 C. 100 D. 76

Mathematics

2 answers:

kirill [66]4 years ago

8 0

Answer:

C. 100

Step-by-step explanation:

To complete this question you must use systems of equations.

First you must complete multiplication or division depending on which comes first in the left to right sequence. In this case it is 125/25 which equals 5. This now makes the equation 75+5 x 5

Next, you complete any other division or multiplication Which in this case is, 5x5. The answer to this is 25, making the new equation, 75+25 which when added together equals 100!

And that is how you use systems of equations. Hope it helps ;)

polet [3.4K]4 years ago

3 0

Answer:

C = 100

Step-by-step explanation:

PEMDAS

multiplication and division first from left to right so

125/25 = 5

5x5 = 25

25 + 75 = 100

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938 divided by 7, pls give the solution too

stellarik [79]

Answer:

134

Step-by-step explanation:

938÷7=134

8 0

3 years ago

Read 2 more answers

Have a go at this one!

Sonbull [250]

Answer:

I THINK 96

Step-by-step explanation:

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7 0

3 years ago

If 2tanA=3tanB then prove that,<br>tan(A+B)= 5sin2B/5cos2B-1

Fed [463]

By definition of tangent,

tan(A + B) = sin(A + B) / cos(A + B)

Using the angle sum identities for sine and cosine,

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

yields

tan(A + B) = (sin(A) cos(B) + cos(A) sin(B)) / (cos(A) cos(B) - sin(A) sin(B))

Multiplying the right side by 1/(cos(A) cos(B)) uniformly gives

tan(A + B) = (tan(A) + tan(B)) / (1 - tan(A) tan(B))

Since 2 tan(A) = 3 tan(B), it follows that

tan(A + B) = (3/2 tan(B) + tan(B)) / (1 - 3/2 tan²(B))

… = 5 tan(B) / (2 - 3 tan²(B))

Putting everything back in terms of sin and cos gives

tan(A + B) = (5 sin(B)/cos(B)) / (2 - 3 sin²(B)/cos²(B))

Multiplying uniformly by cos²(B) gives

tan(A + B) = 5 sin(B) cos(B) / (2 cos²(B) - 3 sin²(B))

Recall the double angle identities for sin and cos:

sin(2x) = 2 sin(x) cos(x)

cos(2x) = cos²(x) - sin²(x)

and multiplying uniformly by 2, we find that

tan(A + B) = 10 sin(B) cos(B) / (4 cos²(B) - 6 sin²(B))

… = 10 sin(B) cos(B) / (4 (cos²(B) - sin²(B)) - 2 sin²(B))

… = 5 sin(2B) / (4 cos(2B) - 2 sin²(B))

The Pythagorean identity,

cos²(x) + sin²(x) = 1

lets us rewrite the double angle identity for cos as

cos(2x) = 1 - 2 sin²(x)

so it follows that

tan(A + B) = 5 sin(2B) / (4 cos(2B) + 1 - 2 sin²(B) - 1)

… = 5 sin(2B) / (4 cos(2B) + cos(2B) - 1)

… = 5 sin(2B) / (4 cos(2B) - 1)

as required.

5 0

2 years ago

the logarmithmic functions, f(x)=logx and g(x), are shown on the graph. what is the equation that represents g(x)? explain.

mestny [16]

Answer:

g(x) = log(x+1) + 4

Step-by-step explanation:

If a curve has been translated (shifted or slid) you can add to or subtract from the x to show horizontal (left or right) shifts and add or subtract a number tacked onto the end of the equation to cause the vertical shift (up or down).

The curve for g(x) is shifted left 1 unit. So change the x to x+1. Left and right shifts are a little backwards from what you might think. But left shift is a +1.

Vertical shifts adjust the way you would think they should. UP shift 4 units is a +4 on the end of the equation. See image.

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2 years ago

Eric reflected parallelogram ABCD across the x-axis. If angle A is 125° and angle B is 55°, what is the degree measurement of an

Sauron [17]

The measures of the angles don't change when you translate a figure, because the entire figure is moving as a whole. Imagine having a paper parallelogram, moving it around and flipping it over. Not even dilations would change these angles (for reasons that can be pretty easily visualed but not really proven until geometry)

$m\angle A'=125\°$

7 0

4 years ago