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maksim [4K]
4 years ago
7

Generate the first 5 terms of this sequence:

Mathematics
1 answer:
AURORKA [14]4 years ago
4 0
<span>We are given f(1) = 0 and f(2) = 1. Going forward, the term is the sum of the two previous terms. f(3) = f(2) + f(1) = 0 + 1 = 1. f(4) = f(3) + f(2) = 1 + 1 = 2 f(5) = f(4) + f(3) = 2 + 1 = 3 This matches answer B.</span>
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An elevator has a placard stating that the maximum capacity is 1580 lb-10 passengers.​ So, 10 adult male passengers can have a m
disa [49]

Answer:

a) 0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb

b) No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 160 lb and a standard deviation of ​35 lb.

This means that \mu = 160, \sigma = 35

Sample of 10:

This means that n = 10, s = \frac{35}{\sqrt{10}} = 11.07

a) Find the probability that it is overloaded because they have a mean weight greater than 158 lb.​

This is 1 subtracted by the pvalue of Z when X = 158. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{158 - 160}{11.07}

Z = -0.18

Z = -0.18 has a pvalue of 0.4286

1 - 0.4286 = 0.5714

0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb.

b.) Does this elevator appear to be​ safe?

No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

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3 years ago
A 6-car monorail train can carry 78 people.If the train makes 99 trips during the day,what is the greatest number of people the
Pavlova-9 [17]
If the train can carry 78  people and it makess 99 trips,
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-5^9 ; (5^3)^-2 <---- Neither of these is equal to 1/(5^9)

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Help me if you’re a real one!
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The answer is B. You solve each inequality and you get x is greater than or equal to 1 and x<6 so those two are included in the interval of b. So the answer is B.
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Which choice is equivalent to the expression below?
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The answer to that is C.
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