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Zolol [24]
1 year ago
9

If we add 9 tens 5 hundreds and 3 ones then the result is?

Mathematics
2 answers:
kozerog [31]1 year ago
7 0

Answer:

593

Step-by-step explanation:

9tens =90

5 hundreds=500

3 ones =3

ioda1 year ago
6 0

Answer:

9 tens = 90

5 hundreds = 500

3 ones = 3

on adding them we get, 500 + 90 + 3 = 593

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Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
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\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

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f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

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In part (b), I don't know what is meant by "df/dt for F"...

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\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

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