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Agata [3.3K]
3 years ago
5

Can anyone solve this for me?

lign="absmiddle" class="latex-formula">+9x-6

x = \frac{-1^{2} }{3}
Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer: 9x - 485/81

------------------------------

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Find the complex fourth roots of 81(cos(3π/8)+isin(3π/8)). a) Find the fourth root of 81. b) Divide the angle in the problem by
WARRIOR [948]

Answer:

The answer is below

Step-by-step explanation:

Let a complex z = r(cos θ + isinθ), the nth root of the complex number is given as:

z_1=r^{\frac{1}{n} }(cos(\frac{\theta +2k\pi}{n} )+isin(\frac{\theta +2k\pi}{n} )),\\k=0,1,2,.\ .\ .,n-1

Given the complex number z = 81(cos(3π/8)+isin(3π/8)), the fourth root (i.e n = 4) is given as follows:

z_{k=0}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8}  +2(0)\pi}{4} )+isin(\frac{\frac{3\pi}{8}  +2(0)\pi}{4} ))=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})] \\z_{k=0}=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})]\\\\z_{k=1}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8}  +2(1)\pi}{4} )+isin(\frac{\frac{3\pi}{8}  +2(1)\pi}{4} ))=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})] \\z_{k=1}=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})]\\\\

z_{k=2}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8}  +2(2)\pi}{4} )+isin(\frac{\frac{3\pi}{8}  +2(2)\pi}{4} ))=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})] \\z_{k=2}=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})]\\\\z_{k=3}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8}  +2(3)\pi}{4} )+isin(\frac{\frac{3\pi}{8}  +2(3)\pi}{4} ))=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})] \\z_{k=3}=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})]

3 0
3 years ago
Solve as long multiplication / Show work.(So I can understand the steps)<br><br> $655.84 x 0.062 =
Gennadij [26K]

Answer:

Step-by-step explanation:

1.      655.84

       x    <u>0.0062</u>

          131168

+     393504

   000000

<u>0000000      </u>

0004066208

there are 5 numbers after the decimal point,we count from the back and place our point = 40.66208

8 0
3 years ago
The measure of one angle is six more than half the measure of another angle. If the angles are complementary, find both measures
Snowcat [4.5K]

Answer:

The measures of the two angles are 34° and 56°

Step-by-step explanation:

* Lets explain how to solve the problem

- The complementary angles are the angles whose the sum

  of their measures is 90°

- The measure of one angle is six more than half the measure

 of another angle

- Let the measure of the second angle angle is x

∵ The measure of the 2nd angle is x

∵ The measure of the first angle is 6 more than the half of the

  measure of the second angle

∴ The 1st angle is 6 + 1/2 x

∵ The two angles are complementary

∴ The sum of their measures is 90°

∴ x + (6 + 1/2 x) = 90

∴ (x + 1/2 x) + 6 = 90

∴ 3/2 x + 6 = 90

- Subtract 6 from both sides

∴ 3/2 x = 84

- Multiply both sides by

∴ 3x = 168

- Divide both sides by 3

∴ x = 56

∵ x is the measure of the 2nd angle

∴ The measure of the 2nd angle is 56°

∵ The measure of the 1st angle = 6 + 1/2 x

∵ x = 56

∴ The measure of the 1st angle = 6 + 1/2(56) = 34°

* The measures of the two angles are 34° and 56°

4 0
2 years ago
PLEASE HELP!
andreyandreev [35.5K]

Answer:

2,4,1

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Will Give Brainliest!!!
Musya8 [376]
I think the best answer would be answer D
6 0
3 years ago
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