Answer:
38.8 m/s
Explanation:
Force F(x) = 6 - 2x + 6x²
work
W = mv²/2=7v²/2 = 3.5v² = 5261
v = 38.8 m/s
Answer:
x=2.4t+4.9t^2
Explanation:
This equation is one of the kinematic equations to solve for distance. The original equation is as follows:
X=Xo+Vt+1/2at^2
We know that the ball starts at rest meaning that its initial velocity and position is zero.
X=0+Vt+1/2at^2
Since it is going down the ramp, you can use the acceleration of gravity constant. (9.81 m/s^2) and simplify that with the 1/2.
X=Vt+4.9t^2
Note: Since the positive direction in this problem is down, you are adding the 4.9t^2, but if a question says that the downward direction is negative, you would subtract those values.
Now, substitute in your velocity value.
X=2.4t+4.9t^2
We will apply the equation:2as = v² - u²v = √(2as + u²)v = √(2 x 4 x 400 + 13²)v = 58 m/s
Answer:
e. 425.9 Hz
Explanation:
The computation of the frequency is being played by the out-of-tune key is shown below;
Given that
Δf1 = x - 349.2 = 76.7.........(1)
Δf2 = 440 - x = 14.1......(2)
Now solve (1) and (2)
(440 - x) - x + 349.2 = 14.1 - 76.7
789.2 + (-2x) = -62.6
x = 425.9 Hz
Hence, the frequency is being played by the out-of-tune key is 425.9 Hz
Therefore the option e is correct
Rutherford tested Thomson'shypothesis by devising his "gold foil" experiment. Rutherford was forced to discard the Plum Pudding modeland reasoned that the only way the alpha particles could be deflected backwards was if most of the mass in an atom was concentrated in a nucleus.
