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vekshin1
3 years ago
6

Sonar is used to map the ocean floor. if an ultrasonic signal is received 3.3 s after it is emitted, how deep is the ocean floor

at that location?
Physics
1 answer:
Goryan [66]3 years ago
6 0
The speed of sound in fresh water is 1482m/s. 
It says ocean floor, so we should a little bit more accurate, and use the fact that the speed of sound in salt water (that has no bubbles) is 1560m/s. 
speed = distance / time 
Therefore Distance = speed x time = 1560 x 3.3 = 5158m 
The sonar wave is sent out by the boat, reflected off the seafloor, and then is received back at the boat on the surface. So the distance 5148m is the distance from the boat to the sea bottom and then back up to the boat again. 
So the depth of the water is half this distance Depth of water = 5148/2=2574m
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Burka [1]

Answer:

0.8m/s

Explanation:

Weight of mas,F=763 N

Mass of man=\frac{F}{g}=\frac{763}{9.8}=77.86 kg

By using g=9.8m/s^2

Weight of flatcar=F'=3513 N

Mass of flatcar=\frac{3513}{9.8}=358.5 Kg

Total mass of the system=Mass of man+mass of flatcar=77.86+358.5=436.36 kg

Velocity of system=19.8m/s

Let v be the velocity of flatcar with respect to ground

Velocity of man relative to the flatcar=-4.68m/s

Final velocity of man with respect to ground=v-4.68

By using law of conservation of momentum

Initial momentum=Momentum of car+momentum of flatcar

436.36(19.8)=77.86(v-4.68)+358.5v

8639.928=77.86v-364.3848+358.5v

8639.928+364.3848=436.36 v

9004.3128=436.36v

v=\frac{9004.3128}{436.36}

v=20.6 m/s

Initial speed of flatcar=Speed of system

Increase in speed=Final speed-initial speed=20.6-19.8=0.8m/s

4 0
3 years ago
In a Young's double-slit experiment the separation distance y between the second-order bright fringe and the central bright frin
atroni [7]

Answer:

Y = 0.0254 m = 25.4 mm

Explanation:

The formula for the fringe spacing in Young's Double-slit experiment is given by the following formula:

Y = \frac{\lambda L}{d}

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Y = fringe spacing = 0.0176 m

λ = wavelength = 425 nm = 4.25 x 10⁻⁷ m

L = Distance between screen and slits

d = slit separation

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\frac{0.0176\ m}{4.25\ x\ 10^{-7}\ m} = \frac{L}{d}\\\\\frac{L}{d} =  41411.76

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Y = (6.14\ x\ 10^{-7}\ m)(41411.76)\\

<u>Y = 0.0254 m = 25.4 mm</u>

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3 years ago
The distance from one Crest to the next Crest is the blank
Luda [366]
The distance from one crest to the next crest in a set of waves is called the wavelength. The distance from the crest of one wave to the equilibrium point is called frequency.
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8 0
3 years ago
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Answer:
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3 0
3 years ago
What are electrons and how are they involved in creating and electric current?
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6 0
3 years ago
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