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vekshin1
2 years ago
6

Sonar is used to map the ocean floor. if an ultrasonic signal is received 3.3 s after it is emitted, how deep is the ocean floor

at that location?
Physics
1 answer:
Goryan [66]2 years ago
6 0
The speed of sound in fresh water is 1482m/s. 
It says ocean floor, so we should a little bit more accurate, and use the fact that the speed of sound in salt water (that has no bubbles) is 1560m/s. 
speed = distance / time 
Therefore Distance = speed x time = 1560 x 3.3 = 5158m 
The sonar wave is sent out by the boat, reflected off the seafloor, and then is received back at the boat on the surface. So the distance 5148m is the distance from the boat to the sea bottom and then back up to the boat again. 
So the depth of the water is half this distance Depth of water = 5148/2=2574m
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2 years ago
an 1150kg elevator moving down speeds up at a rate of 3.5m/s. what is the tension in the supporting cables?
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The tension force in the supporting cables is 7245N

Explanation:

There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:

F_{net} = F_g - F = m\cdot g - F\\

We are given the resulting acceleration along with the mass, i.e., we know the net force, allowing us to solve for F:

1150kg\cdot 3.5\frac{m}{s^2}= 1150kg \cdot 9.8\frac{m}{s^2}-F\\\implies F = 1150kg\cdot(9.8-3.5)\frac{m}{s^2}= 7245N

The tension force F in the supporting cables is 7245N


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As per Newton's law rate of change in momentum is net force

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