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4 years ago

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A 1.3 kg booster is attached to a 6.0 kg rocket is initially travelling at a velocity of 175 m/s. If the booster is ejected in b

ackward direction with velocity of 60 m/s relative to the rocket/booster rest frame , how fast will the rocket then travel?

1 answer:

nikklg [1K]4 years ago

4 0

Answer:

It will travel to the infinity and beyond

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PLEASE HELP ASAP

otez555 [7]

Answer:

D: unconscious

Explanation:

Apex have a nice day :)

7 0

4 years ago

Which of the following materials offer the least electrical resistance? Pure water, wood, salt water, glass

Vanyuwa [196]

Salt water offers the least electrical resistance.

<u>Explanation:</u>

Least electrical resistance indicates that any material which readily allows the electric current through itself, and shows more conductivity.

Here pure water doesn't contain any ions, so it is a bad conductor.

Wood and glass are also bad conductors of electricity.

Salt water contains ions, which conducts electricity which means it shows least electrical resistance.

5 0

4 years ago

Water flows through a water hose at a rate of Q1 = 860 cm3/s, the diameter of the hose is d1 = 1.85 cm. A nozzle is attached to

Snowcat [4.5K]

Answer:

a) A1 = $\frac{\pi (d1)^{2} }{4}$

b) A1 = 2.688 cm $^{2}$

c) Q1 = A1 x v1

d) v1 = 3.1994 m/s

e) A2 = $\frac{A1 X v1}{v2}$

f) A2 = 0.7963cm $^{2}$

Explanation:

a) Area = $\pi r^{2}$

r = $\frac{d}{2}$

thus,

area = $\pi (\frac{d}{2})^{2}$

A1 = $\frac{\pi (d1)^{2} }{4}[/tex]b) d1 = 1.85 cmsubstituting in the above equation,A1 = [tex]\frac{\pi (d1)^{2} }{4}$

A1 = $\frac{\pi (1.85)^{2} }{4}$

A1 = 2.688 cm $^{2}$

c) Flow rate = Area x velocity ( refer brainly.com/question/13997998)

Q1 = A1 x v1

d) From the above equation,

v1 = $\frac{Q1}{A1}$ = $\frac{860}{2.688}$ = 319.94 cm/s = 3.1994 m/s

e) Since the flow rate Q1 is constant throughout the hose, Av is a constant.

i.e. A1 x v1 = A2 x v2

thus,

A2 = $\frac{A1 X v1}{v2}$

f) v2 = 10.8 m/s.

substituting the values in the above equation,

A2 = $\frac{2.688 X 3.1994}{10.8}$ = 0.7963cm $^{2}$

3 0

4 years ago

The acceleration of a baseball pitcher's hand as he delivers a pitch is extreme. For a professional player, this acceleration ph

SashulF [63]

Answer:

116 N.

Explanation:

Given,

mass of the ball, m = 0.145 Kg

initial speed = 0 m/s

Final speed = 40 m/s

time = 50 ms = 0.05 s

Force is equal to change in momentum per unit time

$F = \dfrac{m\Delta v}{\Delta t}$

$F = \dfrac{0.145(40-0)}{0.05}$

F = 116 N

Force of the pitcher hand on the ball is equal to 116 N.

4 0

3 years ago

The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of t

Sphinxa [80]

Answer:

The power consumed by the air filter is 9.936 watts

Explanation:

It is given that, the secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter.

Turn ratio of the transformer, $\dfrac{N_s}{N_p}=\dfrac{46}{1}$

Voltage of primary coil, $V_p=120\ V$

Current in the secondary coil, $I_s=1.8\times 10^{-3}\ A$

The power consumed by the air filter is :

$P_s=I_s\times V_s$ ...........(1)

For a transformer, $\dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}$

So, $P_s=I_s\times (\dfrac{N_s}{N_p})\times V_p$

$P_s=1.8\times 10^{-3}\times (\dfrac{46}{1})\times 120$

$P_s=9.936\ Watts$

So, the power consumed by the air filter is 9.936 watts. Hence, this is the required solution.

3 0

4 years ago

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