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3 years ago

in a company 95% of the workers are women if 220 people work for the company who aren't women how many workers are there in all?

1 answer:

7 0

So 5% of workers are not women, and 220 workers are not women, so 220 is 5% of the total workers. 220 is 5% of 4400, so there are 4400 workers in all.

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Which set of points includes all of the solutions for y = negative three halves times x plus two? line going through 0 comma 2 a

worty [1.4K]

Answer:

$(x,-\frac{3}{2} x+2)$

Step-by-step explanation:

For $y= \frac{-3}{2} x+2$ the set of points that include all solutions are $(x,y)$ such that $y= \frac{-3}{2} x+2$ ; then we have $(x,y)=(x,\frac{-3}{2} x+2)$ .

What is important to stress here is that $(x,-\frac{3}{2} x+2)$ represents all of the solutions, while other points that we are given represent one solution (for example, point (2,-1) is just one solution)

5 0

3 years ago

Please Please Please help with this math problem

katovenus [111]

The revenue as a function of x is equal to -x²/20 + 920x.
The profit as a function of x is equal to -x²/20 + 840x - 6000.
The value of x which maximizes profit is 8,400 and the maximum profit is $3,522,000.
The price to be charged to maximize profit is $500.

<h3>How to express the revenue as a function of x?</h3>

Based on the information provided, the cost function, C(x) is given by 80x + 6000 while the demand function, P(x) is given by -1/20(x) + 920.

Mathematically, the revenue can be calculated by using the following expression:

R(x) = x × P(x)

Revenue, R(x) = x(-1/20(x) + 920)

Revenue, R(x) = x(-x/20 + 920)

Revenue, R(x) = -x²/20 + 920x.

Expressing the profit as a function of x, we have:

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = -x²/20 + 920x - (80x + 6000)

P(x) = -x²/20 + 840x - 6000.

For the value of x which maximizes profit, we would differentiate the profit function with respect to x:

P(x) = -x²/20 + 840x - 6000

P'(x) = -x/10 + 840

x/10 = 840

x = 840 × 10

x = 8,400.

For the maximum profit, we have:

P(x) = -x²/20 + 840x - 6000

P(8400) = -(8400)²/20 + 840(8400) - 6000

P(8400) = -3,528,000 + 7,056,000 - 6000

P(8400) = $3,522,000.

Lastly, we would calculate the price to be charged in order to maximize profit is given by:

P(x) = -1/20(x) + 920

P(x) = -1/20(8400) + 920

P(x) = -420 + 920

P(x) = $500.

Read more on maximized profit here: brainly.com/question/13800671

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3 0

2 years ago

What is the sum of the squares of the lengths of the $\textbf{medians}$ of a triangle whose side lengths are $10,$ $10,$ and $12

FrozenT [24]

A picture can help.

The median to the long side divides the isosceles triangle into two right triangles with hypotenuse 10 and short leg 6. Thus the long leg (median of interest) is found by the Pythagorean theorem to be

... √(10² -6²) = √64 = 8

Then the midpoint of the short side is found to be 6 + (6/2) = 9 units to the side and 8/2 = 4 units above the opposite vertex. Hence the square of the length of that median is 9² + 4² = 97.

The sum of squares of interest is

... 8² + 2×97 = 258