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3 years ago

What is 9.34 kl = to dal

Mathematics

1 answer:

charle [14.2K]3 years ago

6 0

One kiloliter is equal to one hundred dekaliters. Multiply $9.43*100$ to get your answer :)

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Colin invests £3900 into his bank account.

zloy xaker [14]

Answer:

Colin will have 421824 pennies after 2 years

Step-by-step explanation:

Given:

Amount invested in bank by Colin (P) = £3900

Rate of interest (r) = 4%

Time period (n) = 2 years

To find: Amount after 2 years (A)

Solution:

Formula for amount (A) is $A=P\left ( 1+\frac{r}{100} \right )^n$

$A=3900\left ( 1+\frac{4}{100} \right )^2\\=3900\left ( 1+\frac{1}{25} \right )^2\\=3900\times \frac{26}{25}\times \frac{26}{25}\\=4218.24$

As 1 pound = 100 pennies,

4218.24 pounds = 4218.24 × 100 = 421824 pennies

So,

Colin will have 421824 pennies after 2 years.

4 0

2 years ago

You are single and employed full-time as a manager. You have no children. Your gross income is $49,500. You contributed $1,800 t

Alex777 [14]

That is the final answer to this question
42765

4 0

3 years ago

2x — бу = 12<br> х+ 10 = — 9

Serggg [28]

Answer:

x = -19; y = 25/3

Step-by-step explanation:

Step 1: solve the equation with only one variable

Isolate the variable (x)

x + 10 = -9

x = -9 - 10

x = -19

Step 2: input new information into the other equation

If x = -19, then:

2(-19) - 6y = 12

Isolate the variable (y)

-38 - 6y = 12

-6y = 12 + 38

-6y = 50

y = 50 ÷ 6

y = 50/6

Simplify

y = 25/3

5 0

3 years ago

The diameter of a sphere is 4 centimeters. Which represents the volume of the sphere?

frosja888 [35]

Answer:

256π/3 cm³

Step-by-step explanation:

d = 2r => r = d/2 = 4cm/2 = 2 cm

V(sphere) = 4π·r³/3

= 4π·64/3 cm³

= 256π/3 cm³

7 0

3 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago