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charle [14.2K]
3 years ago
6

Write an equation in point-slope form of the line that passas through the point (-6,6) and has a slope of m=3/2

Mathematics
1 answer:
horrorfan [7]3 years ago
5 0

Answer:

2

Step-by-step explanation:

3

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Solutions to 2 variables equations
pychu [463]

Answer:

C) both

Step-by-step explanation:

-4x+7=2y-3

Plug in

(2,1)

-4(2) +7 = 2(1)-3

-8 + 7 = 2 - 3

-1 = -1

So (2,1) is the solution

(5,-5)

-4(5) +7 = 2(-5)-3

-20 + 7 = -10 - 3

-13 = -13

So (5,-5) is the solution

Answer:

C) both

8 0
4 years ago
Simplify.<br><br> 4−16÷4+42<br><br> −16<br> 13<br> 15<br> 16<br>PLEASE HELP
jok3333 [9.3K]
PEMDAS. 16/4 = 4. 4+42 = 46. 46-4 = 42. Answer is 42!
3 0
3 years ago
Read 2 more answers
Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 132 mg/dL and
Lelechka [254]

Answer:

134.6

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula. This is X when Z has a p-value of 1-0.01 = 0.99. So it is X when Z = 2.325.

The level is L = 134.6

The Central Limit Theorem estabilishes that, for a random variable X, with mean  and standard deviation, large sample size can be approximated to a normal distribution with a mean and standard deviation

8 0
3 years ago
What is a numeric amount
Marina CMI [18]

Answer:Numerical digits are the number text characters used to show numerals. For example, the numeral "56" has two digits: 5 and 6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If michael jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time
spin [16.1K]
The formula for the vertical height, h, attained with a vertical take off speed of u is
u² - 2gh = 0
where
g = 9.8 m/s², acceleration due to gravity.

Because h = 1.29 m, therefore
u² = 2*9.8*1.39 = 27.244
u = 5.2196 m/s

Also, the time of flight, t, required when the vertical take-off speed is u is given by
ut  - 0.5gt² = 0.
Therefore
5.2196t - 0.5*9.8*t² = 0
5.2196t - 4.9t² = 0
t(5.2196 - 4.9t) = 0
t = 0, or t = 5.2196/4.9 = 1.0652 s

t = 0 corresponds to take-off.
t = 1.0652 s corresponds to landing.
The hang time is 1.0652 s.

Answer:
Take-off speed = 5.22 m/s (nearest hundredth)
Hang time  = 1.065 s (nearest thousandth)

7 0
3 years ago
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