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sergejj [24]
3 years ago
9

Proving (a + b)^2 = a^2 +2ab + b^2

Mathematics
1 answer:
Natalka [10]3 years ago
6 0

yes this is solved by the distributive property of multiplication.

{(a + b)}^{2}  = (a + b)(a + b)

=  {a}^{2}  + ab +  {b}^{2}  + ab

{a}^{2}  + 2ab +  {b}^{2}

therefore

{(a + b)}^{2}  =  {a}^{2}  +  {b}^{2}  + 2ab

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