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Stella [2.4K]
4 years ago
15

4p+2p when simplifying

Mathematics
1 answer:
ale4655 [162]4 years ago
3 0
Four p plus two p is six p
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What is the domain of g/f if
schepotkina [342]

The domain of g(f(x)) is all the real numbers.

  • f(x) = x-5
  • g(x) = x²
  • In mathematics, function composition is an operation that takes two functions, f and g, and creates a function, h = g(f(x)), such that h(x) = g. The function g is applied in this operation on the outcome of applying the function f to x.
  • g(f(x)) = g(x-5)
  • g(f(x)) = (x-5)²
  • The collection of potential inputs into a function, or the set of input values for which the function is defined, is known as the domain of the function.
  • To find the domain, we find the values for which the function is defined in real values.
  • g(f(x)) is defined when (x-5)² is defined.
  • (x-5)² is defined for all the real numbers.

To learn more about domain, visit :

brainly.com/question/28135761

#SPJ9

5 0
2 years ago
How many tenths are there in 4/5
Harman [31]
There's 0.80 because 4/5 ×20/20 =80/100 And you can turn that into a decimal
7 0
3 years ago
Describe the error.
murzikaleks [220]

Answer:

C. both A and B

Step-by-step explanation:

The student incorrectly applied the Distributive Property in Step 1 by not multiplying 8 and 7. Then they added 7 to 7 to cancel them out, but subtracted 7 from 75 instead of adding like they did on the other side of the equal sign.

3 0
3 years ago
Read 2 more answers
What is the missing term in the geometric sequence? -6,24 ,? ,384,-1536
FromTheMoon [43]
Assume the missing sequence is x 
so -1536 / 384 = x / 24 
so x = (24* - 1536) / 384 
so x = -96 
the answer is C. -96 
7 0
3 years ago
Read 2 more answers
Which expression is equivalent to ​
True [87]

Answer:

2^{\frac{5}{12}}

Step-by-step explanation:

  • The original expression \sqrt{2^5} ^{\frac{1}{4}} can be transformed into (2^{\frac{5}{3}})^{\frac{1}{4}} : both expressions are equivalent, the root of certain number is equivalent to that number power at a fraction whose denominator is the index of the root. The simpliest example for this statement is \sqrt{x} =x^{\frac{1}{2}} (the squared root of x equals x raised at 1/2).
  • Now, the expression(2^{\frac{5}{3}})^{\frac{1}{4}} can be simplified by using the power of a power property, which simply states that if b\neq 0 and ((b)^n)^m=b^{n\times{m}}. In this case, then  (2^{\frac{5}{3}})^{\frac{1}{4}}=2^{\frac{5}{3}\times{\frac{1}{4}}}=2^{\frac{5}{12}}, which is the final expression.
5 0
4 years ago
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