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strojnjashka [21]
3 years ago
5

Find the area and perimeter of an isosceles trapezoid with legs 25cm and bases 16cm and 30cm

Mathematics
2 answers:
Shkiper50 [21]3 years ago
6 0
Perimiter=base1+base2+side1+side2

side1=side2=25
base1=16
base2=30
perimiter=16+30+25+25=96 cm
area of trapezoid=1/2 height times (base1 +base 2)


base 1=16
base2=30

find height
isosolees so
30-16=14
14/2=7
find heigh using:
pythagorean theorem
25^2=7^2+h^2
625=49+x^2
subtract 49 from both sides
576=h^2
square root of both sides
24=h


(base1+base2) times height times 1/2=area
(16+30) times 24 times 1/2=(46) times 12=552 cm^22

the answer is 552 square centimiters or cm^2
and perimiter=96 cm
Varvara68 [4.7K]3 years ago
4 0
<u>A=1/2h(b1+b2)</u>
= 1/2(h)(30+16)
<em>>how to find h<</em>
<em>>30-16= 14/2 = 7<</em>
<em>>25²-7² = 625-49 = 576<</em>
<em>>√576 = 24 .. h=24<</em>
= 1/2(24)(30+16)
= 12(46)
A = 552 cm²
<u>P= b+b+l+l</u>
= 30+16+25+25
P = 96 cm
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<u>Step-by-step explanation:</u>

Here we have , ∠PRS and ∠VUW are supplementary . We need to complete the proof of TV || QS , with matching the reasons with statements .Let's do this :

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