Find the area and perimeter of an isosceles trapezoid with legs 25cm and bases 16cm and 30cm

2 answers:

6 0

Perimiter=base1+base2+side1+side2

side1=side2=25
base1=16
base2=30
perimiter=16+30+25+25=96 cm
area of trapezoid=1/2 height times (base1 +base 2)

base 1=16
base2=30

find height
isosolees so
30-16=14
14/2=7
find heigh using:
pythagorean theorem
25^2=7^2+h^2
625=49+x^2
subtract 49 from both sides
576=h^2
square root of both sides
24=h

(base1+base2) times height times 1/2=area
(16+30) times 24 times 1/2=(46) times 12=552 cm^22

the answer is 552 square centimiters or cm^2
and perimiter=96 cm

Varvara68 [4.7K]3 years ago

4 0

A=1/2h(b1+b2)
= 1/2(h)(30+16)
>how to find h<
>30-16= 14/2 = 7<
>25²-7² = 625-49 = 576<
>√576 = 24 .. h=24<
= 1/2(24)(30+16)
= 12(46)
A = 552 cm²
P= b+b+l+l
= 30+16+25+25
P = 96 cm

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