3 years ago

Find the real solution(s) of the following equation. P3=125

Mathematics

1 answer:

Irina-Kira [14]3 years ago

3 0

$p^3=125\implies p=\sqrt[3]{125}=5$ .

Hope this helps.

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A rate of deposit of dust from unpolluted air is 10.0 tons per square mile per month (30 days). what is this dust fall, in milli

valina [46]

The rate of dust deposition is
$Rate= \frac{10 \,tons}{mi^{2}-30\,days} = \frac{1}{3} \, \frac{tons}{mi^{2}-day}$

Note that
1 ton = 9.07185 x 10⁵ g = 9.07185 x 10⁸ mg
1 mi = 1609.34 m = 1.60934 x 10³ m
1 day = 24 h

Therefore
$Rate=( \frac{1}{3}\, \frac{tons}{mi^{2}-day} )*( \frac{1}{24} \, \frac{day}{h} )*( \frac{1}{1.60934\times10^{3}}\, \frac{mi}{m} )^{2}*(9.07185\times10^{8}\, \frac{mg}{ton})\\= 4.865\, \frac{mg}{m^{2}-h}$

Answer: $4.865\, \frac{mg}{m^{2}-h}$

3 0

3 years ago

SOMEOEN PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1 ITS URGENT PLEASE HELP! 20 POINTS!!!!!

Lesechka [4]

$3q + 5 = - 2q + 20 \\ \Leftrightarrow 5q = 15\Leftrightarrow q = 3$