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Sati [7]
3 years ago
6

A 60-kg person is traveling in a car moving at 16 m/s, when the car hits a barrier. The person is not wearing a seat belt, but i

s stopped by an air bag in a time interval of 0.20 s. Determine the average force that the air bag exerts on the person?
Physics
1 answer:
marin [14]3 years ago
4 0
Using conservation of momentum, we can solve for the force that the air bag exerts on the person.

Recall the equation for momentum (p):

p = mv = F*dt

We can solve for total momentum, then divide by out time interval. This gets us:

(60kg)(16m/s) = F(0.2s)


F = 4800N

F = 4800N


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2. (1) A piece of rubber is 50 cm long when a weight of
Harrizon [31]

Answer

By F = -kx {-ve just indicating the sign of the force}

=>35 = k x (85-50) x 10^-2

=>k = 100 N/m

Again by F = -kx

8 0
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An object is moving initially with a velocity of 4.7 m/s . After 3.9 s the object's velocity is -2.1 m/s . What is the object's
IgorC [24]

Answer: The acceleration of the object is 0.67m/s^2 west.

Explanation: Here we are given the initial velocity and final velocity as well as the time taken. Acceleration is the change in velocity per unit time, thus the equation becomes.

a=dv/t

a=vf-vi/t

a=-2.1-4.7/3.9

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8 0
4 years ago
If you increase the length ? of a pendulum by a factor of 9, how will the period t increase?
garik1379 [7]
T = 2 * pie √(L/g)

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hope it helped :)
3 0
3 years ago
Read 2 more answers
Galilee said that if you rolled a ball along a level surface it would be
lana [24]
The answer would be stay because the surface is flat so it will stay!
3 0
3 years ago
When a gas is heated, it absorbs 196 joules of heat from the surroundings. At the same time, the gas expands, doing pressure-vol
timurjin [86]

Answer:

(a) q positive; w negative.

(b) ΔE = -126 J

(c) E and ΔE

Explanation:

<em>(a) Determine whether the amounts of heat (q) and work (w) exchanged should have positive or negative signs. heat (q) positive negative work (w) positive negative</em>

By convention, when the system absorbs heat from the surroundings, its sign is positive, that is, q = 196 J.

By convention, when the system exerts work on the surroundings, its sign is negative, that is, w = -322 J.

<em>(b) Calculate the change in internal energy (ΔE) of the gas. J</em>

The change in internal energy (ΔE) can be calculated using the following expression.

ΔE = q + w

ΔE = 196 J + (-322 J) = -126 J

<em>(c) Determine whether one or more of the following is a state function: </em>

<em> internal energy (E) of a system, </em>

<em>change in internal energy (ΔE) of a system, </em>

<em>heat (q) absorbed or released by a system, </em>

<em>work (w) done on or by a system.</em>

<em />

E and ΔE are state functions (they only depend on the states of the gas), whereas q and w depend on the trajectory.

7 0
3 years ago
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