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4 years ago

Question 6. B) and c)

Physics

1 answer:

maks197457 [2]4 years ago

4 0

The formula for both is v(t) = v0 + a*t

b) v(8) = 0 + 6m/s^2 *8s = 48 m/s

now we know the beginning (2) and end speed (14), but not the time:

c) 14 = 2 + 1.5*t => t = (14-2)/1.5 = 8 seconds

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A coin has a radius of 1.06 cm and a thickness of 1.2 mm. Find its<br><br> volume in m^3.

ANTONII [103]

Answer:

The volume of the coin is 4.236 x 10⁻⁷ m³

Explanation:

Given;

radius of a coin, r = 1.06 cm = 0.0106 m

thickness of the coin, h = 1.2 mm = 0.0012 m

The volume of the coin is given by;

volume = Area x thickness

Area of the coin = πr² = π (0.0106)² = 3.5304 x 10⁻⁴ m²

The volume of the coin = (3.5304 x 10⁻⁴ m²) x (0.0012 m)

The volume of the coin = 4.236 x 10⁻⁷ m³

Therefore, the volume of the coin is 4.236 x 10⁻⁷ m³

4 0

3 years ago

A hard drive disk rotates at 7200 rpm. The disk has a diameter of 5.1 in (13 cm). What is the speed of a point 6.0 cm from the c

ExtremeBDS [4]

Answer:

The speed will be "3.4×10⁴ m/s²".

Explanation:

The given values are:

Angular speed,

w = 7200 rpm

i.e.,

= $7200 \times \frac{2 \pi}{60}$

= $753.6 \ rad/s$

Speed from the center,

r = 6.0 cm

As we know,

⇒ Linear speed, $v=wr$

On putting the estimated values, we get

$=753.6\times 0.06$

$=45.216 \ m$

Now,

Acceleration on disk will be:

⇒ $a=\frac{v^2}{r}$

$=34074 \ m/s^2$

$=3.4\times 10^4 \ m/s^2$

3 0

3 years ago

What is the pressure at the very bottom of a lake, which is 432 ft deep? (assume an air pressure of 1.013 ✕ 105 pa.)?

aleksley [76]

Preasure at the bottom would be Air Pressure at the top added to the pressure due to the water height.
so pressure = air pressure + hdg
where,
h = depth of the lake, (432ft into metres)
d = density of water (1000kg/m^3)
g = 9.81 m/s^2 (approx.)

8 0

4 years ago

Is the time in Tennessee the same as florida

geniusboy [140]

I would say the same thing as the first answer

5 0

3 years ago

Read 2 more answers

You attach a meter stick to an oak tree, such that the top of the meter stick is 2.07 meters above the ground. Later, an acorn f

ra1l [238]

Answer:

5.05 m

Explanation:

length of stick (L) = 1 m

distance from the top of the stick to the ground (d) = 2.07 m

time taken for corn to travel the length of the stick (t) = 0.121 s

acceleration due to gravity (a) = 9.8 m/s^{2}

we can get the distance in four stages.

Finding the velocity the corn was moving at from $s=vt+0.5at^{2}$

where s = length of stick, t = time, a = acceleration due to gravity

$s=vt+0.5at^{2}$

1 = 0.121u + (0.5 x 9.8 x 0.121 x 0.121)

1 = 0.121v + 0.0717

1 - 0.0717 = 0.121v

v = 7.67 m/s

Using the velocity above to find the time it took for the corn to fall to the top of the stick from the formula v = u + at' where:

v = final velocity = 7.67 m/s

u = initial velocity = 0 m/s since it was initially at rest

a = acceleration due to gravity

t' = time taken to fall to the top of the stick

7.67 = 0 + (9.8 x t')

t' = 7.67 / 9.8 = 0.78 s

using the time above to find the distance between the branch the corn falls from and the top of the stick using $s=vt+0.5at^{2}$ where:

s = distance

v = initial velocity = 0 m/s since it was initially at rest

t = time = 0.78 s

a = acceleration due to gravity = 9.8

s = 0 + (0.5 x 9.8 x 0.78 x 0.78)

s = 2.98 m

Add the distance between the branch the corn falls from and the top of the stick and the distance from the top of the stick to the ground.

2.98 + 2.07 = 5.05 m

5 0

3 years ago