Answer:
-390 mph
Step-by-step explanation:
Let a and b represent, respectively, the distances of A and B from the airport. The distance d between the planes is then given by the Pythagorean theorem as ...
d² = a² + b²
Differentiating with respect to time, we have ...
2d·d' = 2a·a' +2b·b'
Solving for d', we get ...
d' = (a/d)a' +(b/d)b'
The value of d at the time of interest is ...
d = √(a² +b²) = √(30² +40²) = √2500 = 50
Then the rate of change of separation is ...
d' = (30/50)(-250 mph) +(40/50)(-300 mph) = (-150 -240) mph
d' = -390 mph
The distance between planes is decreasing at 390 miles per hour.
Answer:
The last two, 250+25t and 25(10+t)
Step-by-step explanation:
Answer:
(-3,2)
Step-by-step explanation:
If it moved 3 units left, that means the new point's x-coordinate is -3.
If it moved 2 units up, that means the new point's y-coordinate is 2.
Therefore, if the new point's x-coordinate is -3 and y-coordinate is 2, we can represent the point as (-3,2)
Their possibilities will always be at random.
