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3 years ago

The point (5, -2) is rotated 90° about the origin. Its image is:

Mathematics

1 answer:

OLEGan [10]3 years ago

8 0

If rotated around the origin clockwise the new point is found at (-2,-5)

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8. Graph the following linear equations. a. 3x+5y=15

kenny6666 [7]

Answer:

slope: -3/5

y-intercept (0,3)

x - y

0 3

5 0

Step-by-step explanation:

I just did it

4 0

3 years ago

Please help me with this

Cerrena [4.2K]

Answer:

Yes;Each side of triangle PQR is the same length as the corresponding side of triangle STU

Step-by-step explanation:

You can observe the sides of both triangles to see if this property holds

Lets check the length of AB

A(0,3) and B(0,-1)

$AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\\\\\AB=\sqrt{(0-0)^2+(-1-3)^2} \\\\\\\\AB=\sqrt{0^2+-4^2} \\\\\\AB=\sqrt{16} =4units$

Now check the length of the corresponding side DE

D(1,2) and E(1,-2)

$DE=\sqrt{(1-1)^2+(-2-2)^2} \\\\\\DE=\sqrt{0^2+-4^2} \\\\\\DE=\sqrt{16} =4units$

The side AB has the same length as side DE.This is also true for the remaining corresponding sides.

6 0

4 years ago

-x + 1/2 = x + 41/2 *PLEASE SHOW WORK*

ollegr [7]

-x + 1/2 = x + 4 1/2
  +x           +x
         1/2 = 2x + 4 1/2
       -4 1/2       - 4 1/2
        -4 = 2x
         x = -2

6 0

3 years ago

Find the value of y, rounded to the nearest tenth. Please help me, I'd appreciate it!!

Blababa [14]

If a secant and a tangent of a circle are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.

y² = 7(15+7)
y² = 7*22
y² = 154
y = √154
y = 12.4 ← to the nearest tenth

8 0

3 years ago

46 decreased by twice the number

snow_lady [41]

-46

Hope this helps!

May I please have brainliest? :D

4 0

3 years ago

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