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MArishka [77]
3 years ago
13

Write the equation of the line

Mathematics
1 answer:
Svet_ta [14]3 years ago
5 0

Answer:

y = mx+b is how you usually do it to solve



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A rug is to be centered in a room so that the border around it is of a consistent width on all four sides. If the room is 10 ft
aleksley [76]

Answer:

The width of the border can be 9 feet or 3.5 feet.

Step-by-step explanation:

Let the width be x

Length of room = 10 feet

Breadth of room = 15 feet

Length of rug = 10-2x

Breadth of rug = 15-2x

Area of rug = (10-2x)(15-2x)  

We are given that the area of the rug is 24 square feet.

So,  (10-2x)(15-2x)=24 ---A

150-20x-30x+4x^2=24

150-24-50x+4x^2=0

126-50x+4x^2=0

2(x-9)(2x-7)=0

x=9,\frac{7}{2}

x=9,3.5

Substitute x =9 in A

(10-2(9))(15-2(9))=24

24=24

LHS = RHS

Substitute x = 3.5

(10-2(3.5))(15-2(3.5))=24

24=24

LHS = RHS

So, The width of the border can be 9 feet or 3.5 feet.

7 0
4 years ago
Please help me with this one, I’m really stuck on it.
ANTONII [103]
I don’t know if this will help but here you go

6 0
3 years ago
Select from the drop-down menus to correctly complete the sentence. The probability of a compound event is a number between 1.__
scoray [572]
The probability of any event is between 0 and 1. 0 means impossible and 1 means certain.

It could also be written with the percents: 0% and 100%.
5 0
4 years ago
Read 2 more answers
Anyone know the answer?
jonny [76]
Answer is 4 so C for you. I just did this with my brother! Hope this helped.
8 0
3 years ago
Read 2 more answers
A farmer has 64 feet of fence to enclose a rectangular vegetable garden. which dimensions would result in the biggest area for t
Blababa [14]
The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches

7 0
3 years ago
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