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andrew-mc [135]
3 years ago
15

What motion does a ball have when it is rolling

Physics
2 answers:
ankoles [38]3 years ago
6 0
It will have a forward motion.
Ratling [72]3 years ago
3 0

Answer:

Below

Explanation:

It has a forward motion.

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Can someone please help me with part a and d
Temka [501]

Answer: question D is trough

Explanation: I learned this already

7 0
3 years ago
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The age of a piece of wood from an archeological site is to be determined using the Carbon-14 method. The activity of the sample
Bezzdna [24]

Answer:

4589.05 year

Explanation:

The relation of activity is given by A=A_0e^{\lambda t} we have given \frac{A}{A_0}=0.574

Half life T=5730\ years

We know that half life T=\frac{0.693}{\lambda }

\lambda =\frac{0.693}{5730}=1.2094\times 10^{-4}\ per\ year

So 0.574=e^{-1.2094\times 10^{-4}t}

e^{1.2094\times 10^{-4}t}=\frac{1}{0.574}=1.742

{1.2094\times 10^{-4}t}=ln1.742=0.555

t=\frac{0.555}{1.2094\times 10_{-4}}=4589.05\ year

7 0
3 years ago
If the Moon rises at a given location at 6:00 p.m. today, about what time will it rise tomorrow night?
Lena [83]

Answer:

6:50 PM

Explanation:

The Moon continually moves on ahead in its orbit while the Earth rotates. So 24 hours after, the Earth has rotated back around to the same place it was the night before, while the Moon has gone on ahead. assume of it like the second hand on an analog watch, it’s going around the face of the clock much faster than the minute hand, but each time the second hand goes around, the minute hand has moved, and so it takes an extra second to line back up with the minute hand. Because the Moon has moved 13 degrees or so since its last moon rise, it’s going to take another hour or so for the Earth to catch back up to the Moon’s new location, delaying the Moon's rising above your horizons by ~50 minutes each day.

3 0
3 years ago
A rotating space station is said to create "artificial gravity" - a loosely-defined term used for an acceleration that would be
FrozenT [24]

Answer:

\omega=0.31\frac{rad}{s}

Explanation:

The artificial gravity generated by the rotating space station is the same centripetal acceleration due to the rotational motion of the station, which is given by:

a_c=\frac{v^2}{r}(1)

Here, r is the radius and v is the tangential speed, which is given by:

v=\omega r(2)

Here \omega is the angular velocity, we replace (2) in (1):

a_c=\frac{(\omega r)^2}{r}\\\\a_c=\omega^2r

Recall that r=\frac{d}{2}=\frac{200m}{2}=100m.

Solving for \omega:

\omega=\sqrt{\frac{a_c}{r}}\\\omega=\sqrt{\frac{9.8\frac{m}{s^2}}{100m}}\\\omega=0.31\frac{rad}{s}

3 0
4 years ago
A substance that accelerates any chemical reaction but is not consumed in the reaction is a _____.
Mandarinka [93]
A. Catalyst. ---------------
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3 years ago
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