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ss7ja [257]
4 years ago
15

Plz help....plzzzzzz!

Physics
2 answers:
Mekhanik [1.2K]4 years ago
8 0
B. digestive system, heart, and lungs

trapecia [35]4 years ago
8 0
The answer is B. Digestive system, heart, and lungs. These are the most common things most mammals have
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Can anyone answer this question its a science question NO LINKS !!!!
liubo4ka [24]

Answer: Change

Explanation:

5 0
3 years ago
A harmonic wave on a string is described by
xxMikexx [17]

\huge{\bold{\orange{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

A harmonic wave on a string is described by

\sf{ Y( x, t)  = 0.1 sin(300t + 0.01x + π/3)}

  • x is in cm and t is in seconds

<h3><u>Answer </u><u>1</u><u> </u><u>:</u><u>-</u></h3>

<u>Equation </u><u>for </u><u>travelling </u><u>wave </u><u>:</u><u>-</u>

\sf{ Y( x, t)  = Asin(ωt + kx + Φ)...eq(1)}

<u>Equation</u><u> </u><u>for </u><u>stationary </u><u>wave </u><u>:</u><u>-</u>

\sf{ Y( x, t)  = Acos(ωt - kx )...eq(2)}

<u>Given </u><u>equation </u><u>for </u><u>wave </u><u>:</u><u>-</u>

\sf{ Y( x, t)  = 0.1 \:sin(300t + 0.01x + π/3)...eq(3)}

<u>On </u><u>comparing </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>,</u><u> </u><u>(</u><u>2</u><u>)</u><u> </u><u>and </u><u>(</u><u>3</u><u>)</u>

We can conclude that, Given wave represent travelling wave.

<h3><u>Answer </u><u>2</u><u> </u><u>:</u><u>-</u></h3>

From solution 1 , We can say that,

\sf{ Y( x, t)  = 0.1 \: sin(300t + 0.01x + π/3).}

It is travelling from right to left direction

Hence, The direction of its propagation is right to left that is towards +x direction.

<h3><u>Answer </u><u>3</u><u> </u><u>:</u><u>-</u></h3>

Here, We have to find the wave period

<u>We </u><u>know </u><u>that</u><u>, </u>

Wave period = wavelength / velocity

<u>Wave </u><u>equation</u><u> </u><u>:</u><u>-</u>

\sf{ Y( x, t)  = 0.1 \:sin(300t + 0.01x + π/3).}

  • ω = 300rad/s
  • k = 0.01

<u>We </u><u>know </u><u>that</u><u>, </u>

\sf{v =}{\sf{\dfrac{ ω}{2π}}}{\sf{\: and\:}}{\sf{ λ =}}{\sf{\dfrac{ 2π}{k}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ wave\: period =}{\sf{\dfrac{ 2π/k}{ω/2π  }}}

\sf{ wave \:period = }{\sf{\dfrac{k}{ω}}}

\sf{ wave\: period =}{\sf{\dfrac{ 0.01}{300}}}

\sf{ wave\: period = 0.000033\: s}

<h3><u>Answer </u><u>4</u><u> </u><u>:</u><u>-</u></h3>

The wavelength of given wave

\bold{ λ = }{\bold{\dfrac{2π}{k}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ λ = }{\sf{\dfrac{2 × 3.14 }{0.01}}}

\sf{ λ = }{\sf{\dfrac{6.28}{0.01}}}

\sf{ λ = 628 \: cm }

<h3><u>Answer </u><u>5</u><u> </u><u>:</u><u>-</u></h3>

We have wave equation

\sf{ Y( x, t)  = 0.1 sin(300t + 0.01x + π/3).}

<u>Travelling </u><u>wave </u><u>equation </u><u>:</u><u>-</u>

\sf{ Y( x, t)  = A\:sin(ωt + kx + Φ)...eq(1)}

<u>Therefore</u><u>, </u>

Amplitude of the wave particle

\sf{ A = 0.1 \: cm}

Hence, The amplitude of the particle is 0.1 cm

8 0
2 years ago
Terminal velocity. A rider on a bike with the combined mass of 100kg attains a terminal speed of 15m/s on a 12% slope. Assuming
Firlakuza [10]

Answer:

0.9378

Explanation:

Weight (W) of the rider = 100 kg;

since 1 kg = 9.8067 N

100 kg will be = 980.67 N

W = 980.67 N

At the slope of 12%, the angle θ is calculated as:

tan \ \theta = \dfrac{12}{100} \\ \\  tan \ \theta = 0.12 \\ \\  \theta = tan^{-1}(0.12) \\\\ \theta = 6.84^0

The drag force D = Wsinθ

\dfrac{1}{2}C_v \rho AV^2 = W sin \theta

where;

\rho = 1.23 \ kg/m^3

A = 0.9 m²

V = 15 m/s

∴

Drag coefficient C_D = \dfrac{2 *W*sin \theta}{\rho *A *V^2}

C_D =\dfrac{2 *980.67*sin 6.84}{1.23 *0.9 *15^2}

C_D =0.9378

8 0
3 years ago
Definiti: a)Marimile Fizice Vectoriale <br> b)Fortele Concurente
strojnjashka [21]

No lo se hsjdhdhfhjdhshdhdhhd

5 0
3 years ago
During an all-night cram session, a student heats up a 0.607 liter (0.607 x 10- 3 m3) glass (Pyrex) beaker of cold coffee. Initi
mina [271]

Answer: 0.00000938422m^3

Explanation:

dV=Vø*β*(t1-tø)

The parameters are

dV is the change in volume after temperature increase

Vø =0.607 *10^-3m3 is the initial vokume of coffe at 16.2^0 C

β= coefficient of volume expansion of water at 16.2^0 C is 0.0002/0C

t1= 93.5^0C final temperature

tø=16.2^0 C

Therefore

dV=0.607 *10^-3 *0.0002*(93.5-16.2)

dV= 0.00000938422m^3

This is the volume of coffee that will spill over the container

4 0
3 years ago
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