Answer:
(A) 4.75 m/s^{2}
(b) 81.5°
Explanation:
radius (r) = 0.38 m
initial angular velocity (ω') = 1.5 rad/s
angular acceleration (α) = 2 rad/s^{2}
time (t) = 0.5 s
(A) tangential acceleration (a) = α x r
a = 2 x 0.38 = 0.76 rad/s^{2}
- radial acceleration (a') =
final angular velocity (ω) = ω + αt
ω = 1.5 + (2 x 0.5) = 3.5 m/s
a' = = 4.7 m/s^{2}
- total acceleration =
total acceleration = = 4.75 m/s^{2}
(B) tanθ
θ=
θ= = 81.5°
Answer:
light itself doesn't have a shadow
Explanation:
light emits light to where things around the light may create the shadows
The magnitude of the magnetic field on the axis of the ring 5 cm from its center is 143 pT.
The radius of the nonconducting ring is R = 10 cm.
The ring is uniformly charged q = 10 μC.
The angular speed of the ring, ω = 20 rad/s
The ring is x = 5 cm from the center of the ring.
Now,
R = 10 cm = 0.1 m
q = 10.0 μC = 10 × 10⁻⁶ C
x = 5 cm = 0.05 m
The magnetic field on the axis of a current loop is given as:
B = [ μ₀ IR² ] / [4π(x² + R²)^{3/2} ]
Now, I = q / [2π/ω]
So, the magnitude of the magnetic field which is directed away from the center is:
B = [ μ₀ ωqR² ] / [4π(x² + R²)^{3/2} ]
B = [ μ₀ (200) (10 × 10⁻⁶) (0.1)² ] / [4π((0.05)² + (0.1)²)^{3/2} ]
B = 1.43 × 10⁻¹⁰ T
B = 143 pT
Learn more about the magnetic field here:
brainly.com/question/14411049
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100-25=75
speed=distance/time so time=distance/speed
75/15 =5 seconds
I am positive with my and answer and i think yes