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3 years ago

5

Can someone please help me with part a and d

2 answers:

Temka [501]3 years ago

7 0

Answer: question D is trough

Explanation: I learned this already

Semenov [28]3 years ago

4 0

Answer:

'a' is the crest while 'd' is the trough

Explanation:

'a' is the crest of the wave and it is defined as the maximum displacement of a wave from its initial position. The value of crest is a positive amplitude.

'd' is known as the trough and is the defined as the minimum displacement of an object from its initial position to produce a wave motion.

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You can fill a bucket from a downstairs tap quicker than upstairs tap.why?

Zinaida [17]

For filling a bucket from a tap you entirly depend on pressure higher the ground more pressure is needed so slower the flow of water

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3 years ago

The height of a helicopter above the ground is given by h = 3.25t3, where h is in meters and t is in seconds. At t = 2.25 s, the

blondinia [14]

Answer:

In 2.748 sec the mailbag reached the ground

Explanation:

We have given height from the ground $h=3.25t^3$

At t =2.25 sec helicopter releases a small mailbag so at t = 2.25 sec height from the ground $h=3.25t^3=3.25\times 2.25^3=37.01m$

When the mail box is drooped its initial velocity would zero so u = 0 m/sec

Acceleration due to gravity $g=9.8m/sec^2$

According to third law of motion $h=ut+\frac{1}{2}gt^2$

$37.01=0\times t+\frac{1}{2}\times 9.8\times t^2$

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t = 2.748 sec

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3 years ago

What impulse occurs when an average force of 7.0 N is exerted on a cart for 2.5 s ?

makkiz [27]

Answer: $1.7\times 10$

Explanation:

Given

Force $F=7 N$

time interval $t=2.5 s$

Impulse is given by $=Force \times time\ interval\ for\ applied\ force$

$Impulse=7\times 2.5=17.5$

For two significant Figure

$Impulse=1.7\times 10$

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3 years ago

About how many grams are in an ounce of cereal

Pavlova-9 [17]

On Earth, about 29 grams of mass weigh one ounce

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3 years ago

A bicyclist makes a trip that consists of three parts, each in the same direction (due north) along a straight road. During the

Advocard [28]

Answer:

a

The total distance traveled is $D = 26760 \ m$

b

The average velocity is $v_{avg} = 6.8 \ m/s$

Explanation:

From the question we are told that

The time taken for first part $t_1 = 22 \ minutes = 22*60 = 1320 \ s$

The speed for the first part is $v_1 = 7.2 \ m/s$

The time taken for second part is $t_2 = 36 \ minutes = 2160 \ s$

The speed for the second part is $v_2 = 5.1 \ m/s$

The time taken for third part is $t_3 = 8 \ minutes = 480 \ s$

The speed for the third part is $v_3 = 13 m/s$

Generally

$distance(D) = velocity * time$

Therefore the total distance traveled is

$D = (v_1 * t_1) + (v_2 * t_2 ) + (v_3 * t_3)$

substituting values

$D = (7.2 * 1320) + (5.1 * 2160) + (13 * 480)$

$D = 26760 \ m$

Generally the average velocity is mathematically represented as

$v_{avg} = \frac{D}{t_{total}}$

Where $t_{total}$ is the total time taken which is mathematically represented as

$t_{total} = 1320 + 2160 + 480$

$t_{total} =3960\ s$

The average velocity is

$v_{avg} = \frac{26760}{3960}$

$v_{avg} = 6.8 \ m/s$

8 0

3 years ago