Answer:
The answer to the question is 7200
Answer:
14.85 m/s
Explanation:
From the question given above, the following data were obtained:
Height (h) of tower = 45 m
Horizontal distance (s) moved by the balloon = 45 m
Horizontal velocity (u) =?
Next, we shall determine the time taken for the balloon to hit the shoe of the passerby. This is illustrated below:
Height (h) of tower = 45 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
45 = ½ × 9.8 × t²
45 = 4.8 × t²
Divide both side by 4.9
t² = 45/4.9
Take the square root of both side
t = √(45/4.9)
t = 3.03 s
Finally, we shall determine the magnitude of the horizontal velocity of the balloon as shown below:
Horizontal distance (s) moved by the balloon = 45 m
Time (t) = 3.03 s
Horizontal velocity (u) =?
s = ut
45 = u × 3.03
Divide both side by 3.03
u = 45/3.03
u = 14.85 m/s
Thus, the magnitude of the horizontal velocity of the balloon was 14.85 m/s
Answer:
The increase in thermal energy results in an increase in pressure.
Explanation:
- The increase in entropy is directly related to the increase in temperature. So the thermal energy in heat engine increases the temperature of that surrounding.
- Higher temperature means the kinetic energy of particles is also higher, their vibration is increasing. So it increases the pressure (ideal gas law).
- In this way the increment in the thermal energy in heat engine moves piston by increasing the pressure.
Answer:
A) 0.44 rad/s
B) 3.091 rad/s
Explanation:
Initial angular momentum must be equal to final angular momentum.
W1 = 0.80 rad/s
I = 1360 kgm^2
Initial moment Iw = 0.8 x 1360 = 1088 rad-kg-m^2/s
For second case
I = (65 x 4)4.2 + 1360 = 2452 kg-m2-rad/s
New momentum = 2452 x W2
Where w2 = final angular momentum
= 2452W2
Equating both moment,
1088 = 2452W2
W2 = 0.44 rad/s0
If they were on it before,
Initial momentum
I = 1360 - (60 x 4)4.2
= 352 rad-kg-m^2/s
352W1 = 1088
W1 = 3.091 rad/s
