NEED HELP ASAP!!!!!!!!!

Anyone know the answer the answer to this algebra 2 question? Anyone that gets it will give brainiest

viktelen [127]

the answer is x = 2, x = -5

3 0

3 years ago

A gardener is planting two types of trees: Type A is 7 feet tall and grows at a rate of 10 inches per year. Type B is 4 feet tal

trasher [3.6K]

Answer:

9 years

Step-by-step explanation:

Let the the number of years in which height of both the type of tree is same be n years

Initial length of type A tree = 7 feet

As rate of growth is given in inches to maintain uniformity of measuring unit lets convert feet to inches

1 feet = 12 inches

thus 7 feet = 12*7 inches = 84 inches.

length of type A tree in inches = 84 inches

Rate of growth of type A tree = 10 inches per year

Thus, actual growth of type a tree in "n" years = 10*n = 10n

Total height of type A tree in n years = initial length + growth in n years

= 84 inches+ 10n inches (1)

____________________________________________________

For type B

Initial length of type B tree = 4 feet

As rate of growth is given in inches to maintain uniformity of measuring unit lets convert feet to inches

1 feet = 12 inches

thus 4 feet = 12*4 inches = 48 inches.

length of type B tree in inches = 48 inches

Rate of growth of type A tree = 14 inches per year

Thus, actual growth of type a tree in "n" years = 14*n = 14n

Total height of type b tree in n years = initial length + growth in n years

= 48 inches+ 14n inches (2)

_________________________________

Given condition that after n years height of both the type of tree is same

equation 1 should be equal to equation 2

84 inches+ 10n inches = 48 inches+ 14n inches

=>84 inches - 48 inches = 14n inches - 10n inches

=> 36 inches = 4n inches

=> 36 = 4n

=> n = 36/4 = 9

Thus, after 9 years both of their height will be same which be equal to

84+10*9 = 84 + 90 = 174 inches.

5 0

3 years ago

In the midpoint rule for triple integrals we use a triple riemann sum to approximate a triple integral over a box b, where f(x,

Lana71 [14]

The sub-boxes will have dimensions $\frac{2-0}{2} \times \frac{2-0}{2} \times \frac{2-0}{2} =1\times1\times1=1 \ cubic \ units$

x sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $x= \frac{1}{2}$ and $x= \frac{3}{4}$
y sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $y= \frac{1}{2}$ and $y= \frac{3}{4}$
z sub-intervals are 0 to 1 and 1 to 2. Midpoints are at $z= \frac{1}{2}$ and $z= \frac{3}{4}$ 

Let $f(x,y,z)=\cos{(xyz)}$

$\int\limits \int\limits \int\limits {f(x,y,z)} \, dV \approx f\left( \frac{1}{2} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{1}{2} , \frac{3}{4} , \frac{3}{4} \right)$
$+f\left( \frac{3}{4} , \frac{1}{2} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{1}{2} , \frac{3}{4} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{1}{2} \right)+f\left( \frac{3}{4} , \frac{3}{4} , \frac{3}{4} \right) \\ \\ \approx\cos{ \frac{1}{8} }+\cos{ \frac{3}{16} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{3}{16} }+\cos{ \frac{9}{32} }+\cos{ \frac{9}{32} }+\cos{ \frac{27}{64} } \\ \\ \approx0.9922+0.9825+0.9825+0.9607+0.9825+0.9607+0.9607 \\ +0.9123 \\ \\ \approx\bold{7.734}$

5 0

3 years ago

Find the volume of a cylinder with a radius of 6 cm and height 15 cm? (to the nearest whole centimeter) A) 424 cm3 B) 848 cm3 C)

pickupchik [31]

The answer is c) 1696

5 0

3 years ago

Read 2 more answers

Solving each system by eliminating x-y+z= -1 x+y+3z= -3 2x-y+2z= 0

Pie

There's only one system of equations here.

Let's eliminate x first,

x - y + z = -1

x = -1 + y - z

Substituting into x + y + 3z = -3 gives

(-1 + y - z) + y + 3z = -3

2y + 2z = -2

y + z = -1

Substituting for x into 2x-y+2z = 0 gives

2(-1 + y - z) - y + 2z = 0

-2 + 2y - 2z - y + 2z = 0

y = 2

Got lucky on that one.

z = -1 - y = -1 - 2 = -3

x = -1 + y - z = -1 + 2 - -3 = 4

Answer: x=4, y=2, z= -3

Check:

x-y+z = 4 - 2 + -3 = -1, good

x+y+3x = 4+2+3(-3) = -3, good

2x-y+2x = 2(4)-2+2(-3) = 0, good

4 0

4 years ago