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3 years ago

15

Brown ball weighed 1.6 pounds and the green ball weighed 0.39 pounds if he placed both on the scale at the same time what will t

he scale read

1 answer:

NemiM [27]3 years ago

8 0

1.6+0.39 which is 1.99 pounds.

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Answer pls thanks kfdsdatttdfyui8u90g

diamong [38]

Answer:

Step-by-step explanation:

960 75%

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2 years ago

cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0

Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

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3 years ago

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wel

Answer:

d

Step-by-step explanation:

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3 years ago

What is the difference between 7/10-44/100

katrin2010 [14]

Answer:

7/10-44/100 70-44

100

=26/100

=13/50

Step-by-step explanation:

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3 years ago

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Round each number to the nearest hundred and estimate the sum.

murzikaleks [220]

1841 ≈ 1800 (nearest hundred)
964 ≈ 1000 (nearest hundred}

<span>1,841 + 964 </span>≈ 1800 + 1000 = 2800 (Answer B)

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3 years ago

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