Let initially number of fishes =x
He gives 2/3 of his fish to a local high school, that is he gives 2x/3 fish .
So number of fishes left = x -(2x/3) = x/3 . And he gives 2/5 of x/3 to an elementary school , that is , he gives 2x/15 fishes to the elementary school. And finally the number of fishes left =30 , that is




So initially he have 150 fishes .
Answer:
y =4x-6
Step-by-step explanation:
first we have to find the gradient,m
m= y2-y1/x2-x1
= 6-2/3-2
= 4/1
=4
equation : y=mx+c , m=4 , (2,2) [you have only take one point either (2,2) or (3,6) is up to you ;) ]
so , sub the point and gradient into y=mx+c:
2=4(2)+c
2=8+c
2-8=c
-6=c
c=-6
In the end , y =4x-6
hope this help you!! ;)))
69/2 = 24.5
34.5 is the middle of the two integers.
So the two integers would be 34 and 35.
34 + 35 = 69