The odds are 8:7
Hope this helps!!!
А. х²-4=0; х²=4; х=±2, true.
B. x²=-4; there is no solution.
C. 3x²+12=0; 3x²=-12; x²=-4; there is no solution.
D. 4x²=16; x²=4; x=±2, true.
E. 2(x-2)²=0; 2(x²-4x+4)=0; 2x²-8x+8=0; x²-4x+4=0; x1=2; x2=2. False. The answer: A, D.
Answer:
12
Step-by-step explanation:
12 + 15 = 27
15 - 12 = 3
therefore the answers should be 12 becuase 12 is smaller than 15
There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60
To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4. (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4). (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6
Therefore probability is 6/60 = 1/10.
312.5 x 13. Which is <span>4062.5. Then add 1562.5 to get 5625. So by 1998 there would be 5625 bald eagle pairs</span>
