Question

A seven-year medical research study reported that woman whose mothers took the drug DES during pregnancy were twice as likely to develop tissue abnormalities that might lead to cancer as were women whose mothers did not take the drug.For the population of women whose mothers took the drug DES during pregnancy, a sample of 3980 women showed that 63 developed tissue abnormalities that might lead to cancer. Provide a descriptive statistic (to 1 decimal) that could be used to estimate the number of women out of 1,000 in this population who have tissue abnormalities. 63 out of 1,000 women developed tissue abnormalities.

Answer 1

Answer:

Approximatley "16 out of 1,000 women developed tissue abnormalities."

Step-by-step explanation:

For this case we want "to estimate the number of women out of 1,000 in this population who have tissue abnormalities" so then we can said that our parameter of interest is $T$ for example.

We can define the population proportion of who have tissue abnormalities as $p$

And the best estimator for the population proportion is the sample proportion given by $\hat p$ and defined as:

$\hat p =\frac{X}{n}$

Where X represent the number of objects/people who satisfy a characteristic and n is the sample size selected. For our case X=63 and n = 3980. And we can find the estimated proportion like this:

$\hat p = \frac{63}{3980}=0.0158$

We can interpret this like this : " 63 out of 3980 women developed tissue abnormalities".

Or another to interpret this is "Per each 100 women we have approximately 0.01582*1000 =15.82"

So the best answr for this case is: Approximatley "16 out of 1,000 women developed tissue abnormalities."