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3 years ago

Sketch a graph of f(x)

Mathematics

1 answer:

just olya [345]3 years ago

3 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

For $x\leq -2$ -----> the interval is (-∞,-2]

$f(x)=-3$

For $-2 < x \leq 1$ -----> the interval is (-2,1]

$f(x)=x$

For $x > 1$ -----> the interval is (1,∞)

$f(x)=2$

The graph in the attached figure

You might be interested in

Given the triangle below, solve for X.

Dima020 [189]

Answer:

19.8494332413? Sorry I couldn't be more helpful.

Step-by-step explanation:

Use the Pythagorean theorem.

$a^{2}+b^2=c^2\\13^2+15^2=x^2\\169+225=x^2\\394=x^2\\19.8494332413=x


$

5 0

3 years ago

What is the thirty-second term of the arithmetic sequence -12, -7, -2, 3, ... ? Show your work.

anzhelika [568]

The thirty-second term is 143

Further explanation:

As it is already given that the given sequence is an arithmetic sequence

We have to find the common difference first

So,

$a_1=-12\\a_2=-7\\a_3=-2\\a_4=3$

$d=a_2-a_1=-7-(-12)=-7+12=5\\a_3-a_2=-2-(-7)=-2+7=5$

The common difference is 5.

And first term is -12

The explicit formula for arithmetic sequence is:

$a_n=a_1+(n-1)d\\Here,\\a_n\ is\ nth\ term\\a_1\ is\ first\ term\\d\ is\ common\ difference$

Putting the values in the formula

$a_n=-12+(n-1)(5)\\a_n=-12+5n-5\\a_n=-17+5n$

Putting n=32 in explicit formula

$a_{32}=-17+5(32)\\=-17+160\\=143$

The thirty-second term is 143

Keywords: Common difference, Arithmetic Sequence

Learn more about arithmetic sequence at:

#LearnwithBrainly

6 0

3 years ago

A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle’s diagonal measurement is 13 inches, don’

cupoosta [38]

Answer:

The height of rectangle is 5 inches

Step-by-step explanation:

<u><em>The correct question is</em></u>

A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle’s diagonal measurement is 13 inches, Find the height

Let

x -----> the width of the rectangle in inches

y ----> the height of the rectangle in inches

d ---> diagonal measurement of the rectangle in inches

we know that

Applying the Pythagorean Theorem

$d^2=x^{2}+y^{2}$

we have

$d=13\ in$

$13^2=x^{2}+y^{2}$

$169=x^{2}+y^{2}$ ----> equation A

$x=y+7$ ---> equation B

substitute equation B in equation A

$169=(y+7)^{2}+y^{2}$

solve for y

$169=y^2+14y+49+y^{2}$

$2y^2+14y+49-169=0$

$2y^2+14y-120=0$

solve the quadratic equation by graphing

using a graphing tool

The solution is y=5

see the attached figure

therefore

The height of rectangle is 5 inches

5 0

3 years ago

What if I can't answer the questions you give me

Leviafan [203]

Answer:

can u help answer mine

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The area of the bottom of the two cylindrical vessels A and B is 400cm ^ 2 and 300cm ^ 2, respectively. A jar is about 6cm hig

Sonbull [250]

Answer:

Water in container B will be at 6.own

Step-by-step explanation:

calculate the volume in cont. A

VoA=400×6

=2400cm cube

VoB=420ml

=420cm cube [1ml=1cm cube]

now add both volumes

V=2400+420

=2820cm cube

Now,

2820 cm cube in jar B so

2820=420×h

h=6.71

4 0

3 years ago