Answer:
x = 2 and y = 5
Step-by-step explanation:
Given the simultaneous linear equations
y = 2x + 1 and x + y = 7
We are to find the value of x and y;
Substitute 1 into 2
From 2;
x+y = 7
x+2x+1 = 7
3x+1 = 7
3x = 7-1
3x = 6
x = 6/3
x = 2
Recall that y = 2x+1
y = 2(2) + 1
y = 4+1
y = 5
Hence the solution from the graph will be the point where the line cuts the x axis and this will be at x = 2 and y = 5
The answer is 89. it's really not that hard.juat follow the steps
It is B because tangent lines are always perpendicular to radii
Answer:
3/4
Step-by-step explanation:
Reduce both the numerator and the denominator by 10, their greatest common factor.
Confused what the question is. Are you looking for the product or the zeroes?
If you are looking for the product, then:
Use foil to get: sec²(1) - sec²(-csc²) -1(1) -1(-csc²)
= sec² + sec²csc² - 1 + csc²
= sec²csc² + sec² + csc² - 1
= sec²csc² + 1 - 1 (NOTE: sec² + csc² = 1 is an identity)
= sec²csc²
Answer: sec²csc²
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If you are looking for the zeroes, then:
Using the zero product property, set each factor equal to zero and solve.
<u>First factor:</u>
sec²Θ - 1 = 0
sec²Θ = 1
secΘ = 1, -1
remember that secΘ is 
= 1
= -1
cross multiply to get:
cosΘ = 1 cosΘ = -1
use the unit circle (or a calculator) to find that Θ = 0 and π
<u>Second factor:</u>
1 - csc²Θ = 0
1 = csc²Θ
1, -1 = cscΘ
remember that cscΘ is 
= 1
= -1
cross multiply to get:
sinΘ = 1 sinΘ = -1
use the unit circle (or a calculator) to find that Θ =
and
Answer: 0, π,
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