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3 years ago

What is 1.6 + 4x > 14.

Mathematics

2 answers:

Gwar [14]3 years ago

6 0

THE ANSWERS IS 82838382

vlabodo [156]3 years ago

4 0

Answer:

Simplifying

1.6 + 4x = 14

Solving

1.6 + 4x = 14

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1.6' to each side of the equation.

1.6 + -1.6 + 4x = 14 + -1.6

Combine like terms: 1.6 + -1.6 = 0.0

0.0 + 4x = 14 + -1.6

4x = 14 + -1.6

Combine like terms: 14 + -1.6 = 12.4

4x = 12.4

Divide each side by '4'.

x = 3.1

Simplifying

x = 3.1

Step-by-step explanation:

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zmey [24]

Answer:

Let's try and figure it out yearly:

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So that would be 889.98 - 480 = 409.98

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Step-by-step explanation:

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3 years ago

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Lera25 [3.4K]

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3 years ago

What do we mean when we say that a distribution is symmetric?

rusak2 [61]

Answer:

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Step-by-step explanation:

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2 years ago

Can u solve this problem in show your work

aksik [14]

Hey there!

We can solve this problem by doing PEMDAS, which lists:

$Parentheses \\ Exponents \\ Multiplication \\ Division \\ Addition \\ Subtraction$

We have in this equation

$Parentheses \\ Exponents \\ Dvision$

Let's sp;ve this equation now!

Parentheses ↓

$(6 -3) = 3$

Exponents ↓

$3^2 = 9$

Division ↓

$\frac{36}{9} = 9$

Okay now , I show you the steps so it can be easier to solve!

$\frac{36}{(6-3)^2} \\ \\ 6-3 = 3 \\ \\ \frac{36}{3^2} \\ \\ 3^2 = 9 \\ \\ \frac{36}{9} \\ \\ \\ \\ Answer: 4$

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

5 0

3 years ago

Read 2 more answers

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

3 years ago