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3 years ago

What is the value of x.

Mathematics

2 answers:

Ivanshal [37]3 years ago

5 0

Answer:

<U+<V +< W = 180°[sum of interior angle of a triangle is 180°]

3x+9° +30° + 24° = 180°

3x + 45° = 180°

3x = 180° -45° = 135°

x = 135/3

x = 45°

aliina [53]3 years ago

4 0

THEOREM:

Angle sum property —: The sum of interior angles of a triangle is 180°.

ANSWER:

By angle sum property,

∠U + ∠V + ∠W = 180°

3x - 9° + 30° + 24° = 180°
3x + 45° = 180°
3x = 180° – 45°
3x = 135°
x = 135/3
x = 45°

So, Correct choice - [C] 45°.

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There 80 visitors in a local restaurant. There are only two menu options today: chicken or fish. If 20% of the visitors ordered

djverab [1.8K]

Answer:

64 visitors (other 80%)

Step-by-step explanation:

20% of visitors of 80 visitors is 16

So.. 80 - 16 = 64 visitors.

The other 80% of visitors being 64 visitors ordered fish.

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3 years ago

How do I solve The sum of a number and 3 is subtracted from 10 the result is 5

meriva

State the given in the question

Given that the sum of a number and 3 is subtracted from, the result is 5

State what is to be found in the question

We are to find the number. In other to achieve this, we would follow the steps below:

Step 1: Represent the number with an unknown

Let x represent the number

Step 2: Interpret the given statement mathematically

If x is the number, then the sum of the number and 3 would be

$x+3$

Then the sum of a number and 3 subtracted from 10 would be

$10-(x+3)$

Finally, when the sum of a number and 3 subtracted from 10, the result is 5, would be

$10-(x+3)=5$

Step 3: Solve for x in the mathematical interpretation of the given statement

The value of x is as calculated as shown below:

$\begin{gathered} 10-(x+3)=5 \\ \text{Open the bracket or the parenthesis} \\ 10-x-3=5 \\ \text{collect like terms} \\ 10-3-5=x \\ 7-5=x \\ 2=x \\ \text{Therefore:} \\ x=2 \end{gathered}$

Hence, the number is 5

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10 months ago

Find smallest number which on adding to 19 it is exactly divisible by 28,36 and 45 (LCM).

BabaBlast [244]

Answer:

1241

Step-by-step explanation:

∴

L.C.M. of 28, 36 and 45 = 2 × 2 × 3 × 3 × 5 × 7 = 1260

∴

the required number is 1260 - 19 = 1241

Hence, if we add 19 to 1241 we will get 1260 which is exactly divisible by 28, 36 and 45.

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10 months ago

A grocery store offers a 10% discount on your entire purchase when you spend more than $50. You have $117 to spend on groceries

astra-53 [7]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

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3 years ago