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babymother [125]
3 years ago
9

What is the value of x.

Mathematics
2 answers:
Ivanshal [37]3 years ago
5 0

Answer:

<U+<V +< W = 180°[sum of interior angle of a triangle is 180°]

3x+9° +30° + 24° = 180°

3x + 45° = 180°

3x = 180° -45° = 135°

x = 135/3

x = 45°

aliina [53]3 years ago
4 0

THEOREM:

  • Angle sum property —: The sum of interior angles of a triangle is 180°.

ANSWER:

<u>By angle sum property</u>,

∠U + ∠V + ∠W = 180°

  • 3x - 9° + 30° + 24° = 180°
  • 3x + 45° = 180°
  • 3x = 180° – 45°
  • 3x = 135°
  • x = 135/3
  • x = 45°

So, <u>Correct choice</u> - [C] 45°.

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There 80 visitors in a local restaurant. There are only two menu options today: chicken or fish. If 20% of the visitors ordered
djverab [1.8K]

Answer:

64 visitors (other 80%)

Step-by-step explanation:

20% of visitors of 80 visitors is 16

So.. 80 - 16 = 64 visitors.

The other 80% of visitors being 64 visitors ordered fish.

3 0
3 years ago
How do I solve The sum of a number and 3 is subtracted from 10 the result is 5
meriva

State the given in the question

Given that the sum of a number and 3 is subtracted from, the result is 5

State what is to be found in the question

We are to find the number. In other to achieve this, we would follow the steps below:

Step 1: Represent the number with an unknown

Let x represent the number

Step 2: Interpret the given statement mathematically

If x is the number, then the sum of the number and 3 would be

x+3

Then the sum of a number and 3 subtracted from 10 would be

10-(x+3)

Finally, when the sum of a number and 3 subtracted from 10, the result is 5, would be

10-(x+3)=5

Step 3: Solve for x in the mathematical interpretation of the given statement

The value of x is as calculated as shown below:

\begin{gathered} 10-(x+3)=5 \\ \text{Open the bracket or the parenthesis} \\ 10-x-3=5 \\ \text{collect like terms} \\ 10-3-5=x \\ 7-5=x \\ 2=x \\ \text{Therefore:} \\ x=2 \end{gathered}

Hence, the number is 5

4 0
10 months ago
Find smallest number which on adding to 19 it is exactly divisible by 28,36 and 45 (LCM).
BabaBlast [244]

Answer:

1241

Step-by-step explanation:

∴

L.C.M. of 28, 36 and 45 = 2 × 2 × 3 × 3 × 5 × 7 = 1260

∴

the required number is 1260 - 19 = 1241

Hence, if we add 19 to 1241 we will get 1260 which is exactly divisible by 28, 36 and 45.

7 0
10 months ago
A grocery store offers a 10% discount on your entire purchase when you spend more than $50. You have $117 to spend on groceries
astra-53 [7]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen
devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                              P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = \frac{\sum X}{n} = 441

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 14.34

            n = sample size = 16

            \mu = population mean

<em>Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<em />

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.131 < t_1_5 < 2.131) = 0.95  {As the critical value of t at 15 degrees of

                                             freedom are -2.131 & 2.131 with P = 2.5%}  

P(-2.131 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.131) = 0.95

P( -2.131 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.131 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X -2.131 \times {\frac{s}{\sqrt{n} } } , \bar X +2.131 \times {\frac{s}{\sqrt{n} } } ]

                                      = [ 441-2.131 \times {\frac{14.34}{\sqrt{16} } } , 441+2.131 \times {\frac{14.34}{\sqrt{16} } } ]

                                      = [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0
3 years ago
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