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3 years ago

What type of application would be appropriate for learning a foreign language?

Computers and Technology

2 answers:

Marysya12 [62]3 years ago

7 0

Answer:

Education

Explanation:

Most apps for <u>learning</u> a new language are for educational purposes and are most likely an education type of app.

sp2606 [1]3 years ago

3 0

Answer:

Education

Explanation:

The education comes in formal and informal ways.

Formal education

Most schools have classes dedicated to learning foreign languages. For instance, a university can have a writing and language center that has teachers who specialize in different languages. Formal written and spoken assessments are taken to assess the student's competence in a foreign language.

Another way is to take online lessons via an internet conference call or chat.

Informal education

This is when a person learns outside the classroom. However, educational material is used. For instance, a person can download and android app and use it. Another way is to watch videos and learn.

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A vlan ________.

tensa zangetsu [6.8K]

A vlan can span multiple interconnected switches.

A virtual LAN (VLAN) is a logical overlay network that groups together a subset of devices that share a physical LAN, isolating the traffic for each group.

A LAN is a group of computers or other devices in the same place -- e.g., the same building or campus -- that share the same physical network.

Each virtual switch, or VLAN, is simply a number assigned to each switch port.

For example, the two switch ports in the red mini-switch might be assigned to VLAN #10 . The two ports in the orange mini-switch might be assigned to VLAN #20 .

VLANs can be used for different groups of users, departments, functions, etc., without needing to be in the same geographical area.

VLANs can help reduce IT cost, improve network security and performance, provide easier management, as well as ensuring network flexibility.

To learn more about vlan, refer

https://brainly.in/question/2890503

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6 0

1 year ago

In a relational database application, a(n) ________ key is used to link one table with another.

mr_godi [17]

In a relational database application, a <u>foreign key</u> is used to link one table with another.

<h3>What is a foreign key?</h3>

In database management system (DBMS), a foreign key can be defined as a column whose value provides a link between the data that are stored in a table or relational database.

This ultimately implies that, a <u>foreign key</u> is used to link one table with another in a relational database application.

Read more on keys here: brainly.com/question/8131854

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6 0

1 year ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago

Consider this program segment: int newNum = 0, temp; int num = k; // k is some predefined integer value 0 while (num > 10) {

Doss [256]

Answer:

All of these statements are true.

Explanation:

Since the while loop is reversing the integer number and leaving the highest order digit in the num and stores the reversed number in the newNum variable.

It skips one digit so if the num is in the range of [100,1000] it will result in a number between 10 and 100.

This loop can never go in infinite loop for any initial value of num because the loop will run as many times as the number of digits.

and if the value of the num is <=10 the while loop will never run and the value of newNum will be 0.

6 0

3 years ago

If you were programming a robot to respond to touch, the path might look something like this:

aniked [119]

Answer:

what

Explanation:

5 0

3 years ago

Read 2 more answers