Answer:
public class Pyramid {
public static void main(String[] args) {
int h = 7;
System.out.println("Pattern A");
for(int i = 1; i <= h; ++i)
{
for(int j = 1; j <= i; ++j) {
System.out.print("+");
}
System.out.println();
}
System.out.println();
System.out.println("Pattern B");
for (int i = 1; i<=h; ++i)
{
for(int j = h; j >=i; --j){
System.out.print("+");
}
System.out.println();
}
}
}
Explanation:
- The trick in this code is using a nested for loop
- The outer for loop runs from i = 0 to the heigth of the triangle (in this case 7)
- The inner for loop which prints the (+) sign runs from j = 0 to j<=i
- It prints the + using the print() function and not println()
- In the pattern B the loop is reversed to start from i = height
Answer:
- def getLargest(number_list):
- new_list = []
-
- for x in number_list:
- if(isinstance(x, int)):
- new_list.append(x)
-
- largest = max(new_list)
-
- return largest
Explanation:
Firstly, create a function <em>getLargest()</em> that take one input parameter, <em>number_list</em>.
The function will filter out the float type number from the list by using <em>isinstance() </em>method (Line 5). This method will check if a current x value is an integer. If so, the x value will be added to <em>new_list</em>.
Next, use Python built-in <em>max</em> function to get the largest integer from the <em>new_list </em>and return it as output.
Answer:
The correct answer to the following question will be "Disaster Recovery as a Service (DRaaS)".
Explanation:
DRaaS seems to be a cloud services term used only to secure an infrastructure or data through human catastrophe or interruption of service at any destination by allowing a complete recovery throughout the cloud.
- DR seems to be a security or management preparation field which seeks to protect an organisation from those in the consequences of major negative experiences.
- This provides offsite backups which use storage resources to defend programs including assets from disaster-induced destruction.
Solution :
x = float_(input())
y = float_(input())
z = float_(input())
res1 = x**z
res2 = x**(y**z)
res3 = abs(x-y)
res4 = (x**z)**0.5
print('{:.2f} {:.2f} {:.2f} {:.2f}'.format(res1,res2,res3,res4))
Output is :
5.0
1.5
3.2
172.47 361.66 3.50 13.13
