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Vesnalui [34]
3 years ago
6

2(x2 + 5) − 3(x + 1) + 3

Mathematics
1 answer:
mestny [16]3 years ago
7 0

Answer:

2x^2  -3x +10

Step-by-step explanation:

2(x^2 + 5) − 3(x + 1) + 3

Distribute

2x^2 +10 -3x -3 +3

Combine like terms

2x^2    -3x    +10 -3+3

2x^2  -3x +10

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How much pay does john receive if he gives half of his pay to family,250 to his landlord and has exactly 3/7 of his pay left ove
maxonik [38]

Answer:

John receives a pay of $3,500.00

Step-by-step explanation:

x = John's pay

x = 1/2x + 250 + 3/7x     [1/2 = 7/14 and 3/7 = 6/14]

x = 13/14x + 250

x - 13/14x = 13/14x - 13/14x + 250    [1x = 14/14]

1/14x = 250   [multiply both sides by 14]

x = 3500

Check:

3500 = 1/2(3500) + 250 + 3/7(3500)

3500 = 1750 + 250 + 1500

3500 = 3500

 

7 0
3 years ago
1. The figure shows the regular triangular pyramid SABC. The base of the pyramid has an edge AB = 6 cm and the side wall has an
Musya8 [376]

Given:

• AB = 6 cm

,

• SM = √15 cm

Let's solve for the following:

• 1) the base elevation AM.

Given that we have a regular triangular pyramid, the length of the three bases are equal.

AB = BC = AC

BM = BC/2 = 6/2 = 3 cm

To solve for AM, which is the height of the base, apply Pythagorean Theorem:

\begin{gathered} AM=\sqrt{AB^2-BM^2} \\  \\ AM=\sqrt{6^2-3^2} \\  \\ AM=\sqrt{36-9} \\  \\ AM=\sqrt{27} \\  \\ AM=5.2\text{ cm} \end{gathered}

The base elevation of the pyramid is 5.2 cm.

• (2)., The elevation SO.

To find the elevation of the pyramid, apply Pythagorean Theorem:

SO=\sqrt{SM^2-MO^2}

Where:

SM = √15 cm

MO = AM/2 = 5.2/2 = 2.6 cm

Thus, we have:

\begin{gathered} SO=\sqrt{(\sqrt{15})^2-2.6^2} \\  \\ SO=\sqrt{15-6.76} \\  \\ SO=2.9\text{ cm} \end{gathered}

Length of SO = 2.9 cm

• (3). Area of the base:

To find the area of the triangular base, apply the formula:

A=\frac{1}{2}*BC*AM

Thus, we have:

\begin{gathered} A=\frac{1}{2}*6^*5.2 \\  \\ A=15.6\text{ cm}^2 \end{gathered}

The area of the base is 15.6 square cm.

• (4). Area of the side surface.

Apply the formula:

SA=\frac{1}{2}*p*h

Where:

p is the perimeter

h is the slant height, SM = √15 cm

Thus, we have:

\begin{gathered} A=\frac{1}{2}*(6*3)*\sqrt{15} \\  \\ A=34.86\text{ cm}^2 \end{gathered}

• (5). Total surface area:

To find the total surface area, apply the formula:

TSA=base\text{ area + area of side surface}

Where:

Area of base = 15.6 cm²

Area of side surface = 34.86 cm²

TSA = 15.6 + 34.86 = 50.46 cm²

The total surface area is 50.46 cm²

• (6). Volume:

To find the volume, apply the formula:

V=\frac{1}{3}*area\text{ of base *height}

Where:

Area of base = 15.6 cm²

Height, SO = 2.9 cm

Thus, we have:

\begin{gathered} V=\frac{1}{3}*15.6*2.9 \\  \\ V=15.08\text{ cm}^3 \end{gathered}

The volume is 15.08 cm³.

ANSWER:

• 1.) 5.2 cm

,

• 2.) 2.9 cm

,

• 3.) 15.6 cm²

,

• 4.) 34.86 cm²

,

• (5). 50.46 cm²

,

• 6). 15.08 cm³.

7 0
1 year ago
2cos^2A-cos2A-1=0 <br> Help
kondor19780726 [428]

Answer:

steps below

Step-by-step explanation:

Are you going to solve the value of A or just a proof the equation

cos 2A = cos² A - sin² A

2cos²A-cos2A-1 = 2cos²A - (cos² A - sin² A) - 1 = cos² A + sin² A - 1

2cos²A-cos2A-1 = 1 - 1 = 0

A: 90° or 270° or 450° .....

8 0
3 years ago
HELP NEEDED!!! NOW PLZ
liq [111]

Answer:

frick

Step-by-step explanation:

chicken jencdcdhchdbbchdcdccdc

3 0
3 years ago
I need help with this I will mark you if right
kodGreya [7K]
I’m pretty sure it’s c
7 0
3 years ago
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