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makvit [3.9K]
3 years ago
7

When the polynomial in P(x) is divided by (x + a), the remainder equals P(a).

Mathematics
1 answer:
Effectus [21]3 years ago
3 0

According to Remainder Theorem for the polynomials, for every polynomial P(x) there exist such polynomials G(x) and R(x), that P(x)=(x\pm a)G(x)+R(x).


When the polynomial in P(x) is divided by (x + a), then there exist such polynomials G(x) and R(x), that P(x)=(x+a)G(x)+R(x). Note that for x=-a:


P(-a)=(-a+a)G(-a)+R(-a)=0·G(a)+R(-a)=R(-a).
This means that P(-a) is the remainder, not P(a). <span>
</span><span>Answer:<span> correct choice is B.</span></span>




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