A 222 kg bumper car moving right at 3.10 m/s collides with a 165 kg bumper car moving 1.88 m/s left Find the total momentum of t
1 answer:
Answer:
Total momentum of the system is 378 kg-m/s
Explanation:
It is given that,
Mass of first bumper car, m₁ = 222 kg
Velocity of first bumper car, v₁ = 3.10 m/s (in right)
Mass of other bumper car, m₂ = 165 kg
Velocity of second bumper car, v₂ = -1.88 m/s (in left)
Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :
p = 378 kg-m/s
Hence, the total momentum of the system is 378 kg-m/s
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Answer:
100 newtons
Explanation:
Given,
Jamal pushing a large box by a force, F = 100 N
Work done on the large box is, W = 0
It is because the applied force is less than the force of the friction between the two surfaces.
Yet, there will be a force that is exerted by the large box on Jamal.
According to newton's third law of motion, every action has an equal and opposite reaction. The reaction force is in the direction opposite to the force of action. But, their magnitude remains the same.
Hence, If the action force is 100 N, then the reaction force should be in 100 N
Answer:
The average power developed by a motor is 4905 Watts.
Explanation:
The average power is given by:
Where:
W: is the work
t: is the time = 8.0 s
First, let's find the work:
Where:
F: is the force
d: is the displacement = 10.0 m
The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:
Hence, the average power is:
Therefore, the average power developed by a motor is 4905 Watts.
I hope it helps you!