A 222 kg bumper car moving right at 3.10 m/s collides with a 165 kg bumper car moving 1.88 m/s left Find the total momentum of t
1 answer:
Answer:
Total momentum of the system is 378 kg-m/s
Explanation:
It is given that,
Mass of first bumper car, m₁ = 222 kg
Velocity of first bumper car, v₁ = 3.10 m/s (in right)
Mass of other bumper car, m₂ = 165 kg
Velocity of second bumper car, v₂ = -1.88 m/s (in left)
Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :
p = 378 kg-m/s
Hence, the total momentum of the system is 378 kg-m/s
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Answer:
7572 m/s
Explanation:
The force between two masses separated by a distance r is given as:
Where F is the attractive force between 2 masses, m1 and m2, r is the distance between the centres of the masses and G is the universal gravitation constant, which is
The mass of the earth () is far greater than the mass of the sputnik (
). Therefore
. The mass of the sputnik is neglected, therefore:
But F is actually centripetal acceleration, a = v²/r
Answer:
The time is 0.90 sec.
Explanation:
Given that,
Height = 4.00 m
We need to calculate the time
Using equation of motion
For free fall, u = 0
Where, s = distance
g = acceleration due to gravity
t = time
Put the value into the formula
Hence, The time is 0.90 sec.