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Sladkaya [172]
3 years ago
14

A 222 kg bumper car moving right at 3.10 m/s collides with a 165 kg bumper car moving 1.88 m/s left Find the total momentum of t

he system.
Physics
1 answer:
Svetlanka [38]3 years ago
5 0

Answer:

Total momentum of the system is 378 kg-m/s

Explanation:

It is given that,

Mass of first bumper car, m₁ = 222 kg

Velocity of first bumper car, v₁ = 3.10 m/s (in right)

Mass of other bumper car, m₂ = 165 kg

Velocity of second bumper car, v₂ = -1.88 m/s (in left)

Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :

p=m_1v_1+m_2v_2

p=222\ kg\times 3.10\ m/s+165\ kg\times (-1.88\ m/s)

p = 378 kg-m/s

Hence, the total momentum of the system is 378 kg-m/s

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Answer:

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3 years ago
A spatially challenged goldfish swims along the x-axis only. Its initial position is 7.8 m. After swimming back and forth a whil
Verdich [7]

Answer:

<em>The fish displacement was -3.4 m</em>

Explanation:

<u>Distance and Displacement</u>

A moving object constantly travels some distance at defined periods of time. The total moved distance is the sum of each individual distance the object traveled. It can be written as:

dtotal=d1+d2+d3+...+dn

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The displacement only takes into consideration the initial and final points of the path defined by the object in its moving. The displacement, unlike distance, is a vectorial magnitude and can be even zero if the object starts and ends the movement at the same point.

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After some undisclosed movements, it ends up at the position 4.4 m. Thus, the displacement is:

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The fish displacement was -3.4 m

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3 years ago
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A compound is two or more elements combinded together.
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6 0
3 years ago
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