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3 years ago

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One day, five- year old barbara was running down the street. As she opened the gate to her friends yard, a big dog jumped out an

d bite her. She was terribly startled and cried out in pain. She now cries whenever she sees any dog

1 answer:

KatRina [158]3 years ago

7 0

Answer:

instinct

Explanation:

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How does an airplane engine work?

vivado [14]

Answer:

Explanation:

Un motor aeronáutico o motor de aviación es aquel que se utiliza para la propulsión de aeronaves mediante la generación de una fuerza de arrastre.

Existen distintos tipos de motores de aviación, aunque se dividen en dos clases básicas: motores recíprocos —o de pistón— y de turbina de gas. Recientemente y gracias al desarrollo de la NASA y otras entidades, se ha comenzado también la producción de motores eléctricos para aeronaves que funcionen con energía solar fotovoltaica.

eso depende de el motor que cada avion tenga

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3 years ago

Two resistors, of R1 = 3.93 Ω and R2 = 5.59 Ω, are connected in series to a battery with an EMF of 24.0 V and negligible interna

son4ous [18]

Answer:

2.521 (A); 14.0924 (V)

Explanation:

more info in the attachment, the answers are marked with red colour.

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3 years ago

At the local swimming pool, the diving board is elevated h = 8.5 m above the pool surface and overhangs the pool edge by L = 2 m

Tasya [4]

Answer:

Part a)

$t_w = \sqrt{\frac{2h}{g}}$

Part b)

$t_w = 1.32 s$

Part c)

$d_w = 6.88 m$

Explanation:

Part a)

As we know that the diver will have zero velocity in vertical direction

so here we can say that

$\Delta y = v_y t + \frac{1}{2}a_y t^2$

$h = \frac{1}{2}gt^2$

$t_w = \sqrt{\frac{2h}{g}}$

Part b)

as we know that

$h = 8.5 m$

$g = 9.81 m/s^2$

so we will have

$t_w = \sqrt{\frac{2(8.5)}{9.81}}$

$t_w = 1.32 s$

Part c)

Distance covered by diver from the edge of the pool is given as

$d_w = L + v_w t_w$

$d_w = 2 + (3.7)(1.32)$

$d_w = 6.88 m$

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4 years ago

This is the type of reaction that occurs when an acid cancels with a base.

viva [34]

Neutral reaction is the reaction that occurs when an acid cancels with a base

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3 years ago

Read 2 more answers

Two trains on separate tracks move toward each other. Train 1 has a speed of 145 km/h; train 2, a speed of 72.0 km/h. Train 2 bl

tekilochka [14]

Answer:

Therefore,

The frequency heard by the engineer on train 1

$f_{o}=603\ Hz$

Explanation:

Given:

Two trains on separate tracks move toward each other

For Train 1 Velocity of the observer,

$v_{o}=145\ km/h=145\times \dfrac{1000}{3600}=40.28\ m/s$

For Train 2 Velocity of the Source,

$v_{s}=90\ km/h=90\times \dfrac{1000}{3600}=25\ m/s$

Frequency of Source,

$f_{s}=500\ Hz$

To Find:

Frequency of Observer,

$f_{o}=?$ (frequency heard by the engineer on train 1)

Solution:

Here we can use the Doppler effect equation to calculate both the velocity of the source $v_{s}$ and observer $v_{o}$ , the original frequency of the sound waves $f_{s}$ and the observed frequency of the sound waves $f_{o}$ ,

The Equation is

$f_{o}=f_{s}(\dfrac{v+v_{o}}{v -v_{s}})$

Where,

v = velocity of sound in air = 343 m/s

Substituting the values we get

$f_{o}=500(\dfrac{343+40.28}{343 -25})=500\times 1.205=602.64\approx 603\ Hz$

Therefore,

The frequency heard by the engineer on train 1

$f_{o}=603\ Hz$

7 0

4 years ago