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3 years ago

Answer? Quick please.

Mathematics

2 answers:

Scilla [17]3 years ago

8 0

Answer:

5.6

Step-by-step explanation:

All you need to do if solve for the cube root of 176

Volume cube = a^3

3root(176) = 5.604

I hope this helps!

-TheBusinessMan

goblinko [34]3 years ago

7 0

Answer:

5.6 m

Step-by-step explanation:

The volume of a cube can be found using the following formula.

$v=s^3$

We know the volume of the cube is 176 m³, so we can substitute that value in for v, or volume.

$176 m^3=s^3$

We want to find the side length. Therefore, we must get the variable, s, by itself on one side of the equation.

s is being cubed. The opposite of cubed is the cube root. So, take the cube root of both sides of the equation.

$\sqrt[3]{176m^2} =\sqrt[3]{s^3}$

$\sqrt[3]{176m^2} =s$

$5.60407866 m =s$

The question tells us to round to the nearest tenth. The 0 in the hundredth place indicates we should leave the 6 in the tenth place.

$5.6m \approx s$

The side length of the cube is about 5.6 meters.

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3 years ago

Which is a secant of circle A?

sergey [27]

Answer: line CD (fourth choice)

====================================================

Let's go through the choices one by one

1) Segment AB is a radius, which is not a secant line. We can rule this out.

2) line DE is a tangent line which only touches the circle at exactly one spot. We need something that cuts the circle in 2 spots for it to be a secant line. This can also be crossed off the list.

3) segment HG is a chord, which is fairly close to a secant line, but it must extend infinitely in both directions. In other words, it needs to be a line instead of a line segment. This is crossed off the list.

4) line CD is a secant line. It is a geometric line in that it goes on forever in both directions (it's not a segment, and not a ray either). Also, this line crosses the circle at 2 points, which contrasts it from a tangent line. This is the answer we want.

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3 years ago

Can someone help me with this, please & thanks. :)

Rasek [7]

Multiply bath sides by (-13)

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4 years ago

I need help with this problem from the calculus portion on my ACT prep guide

LenaWriter [7]

Given a series, the ratio test implies finding the following limit:

$\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=r$

If r<1 then the series converges, if r>1 the series diverges and if r=1 the test is inconclusive and we can't assure if the series converges or diverges. So let's see the terms in this limit:

$\begin{gathered} a_n=\frac{2^n}{n5^{n+1}} \\ a_{n+1}=\frac{2^{n+1}}{(n+1)5^{n+2}} \end{gathered}$

Then the limit is:

$\lim _{n\to\infty}\lvert\frac{a_{n+1}}{a_n}\rvert=\lim _{n\to\infty}\lvert\frac{n5^{n+1}}{2^n}\cdot\frac{2^{n+1}}{\mleft(n+1\mright)5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert$

We can simplify the expressions inside the absolute value:

$\begin{gathered} \lim _{n\to\infty}\lvert\frac{2^{n+1}}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^{n+1}}{5^{n+2}}\rvert=\lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert \\ \lim _{n\to\infty}\lvert\frac{2^n\cdot2}{2^n}\cdot\frac{n}{n+1}\cdot\frac{5^n\cdot5}{5^n\cdot5\cdot5}\rvert=\lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert \\ \lim _{n\to\infty}\lvert2\cdot\frac{n}{n+1}\cdot\frac{1}{5}\rvert=\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert \end{gathered}$

Since none of the terms inside the absolute value can be negative we can write this with out it:

$\lim _{n\to\infty}\lvert\frac{2}{5}\cdot\frac{n}{n+1}\rvert=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}$

Now let's re-writte n/(n+1):

$\frac{n}{n+1}=\frac{n}{n\cdot(1+\frac{1}{n})}=\frac{1}{1+\frac{1}{n}}$

Then the limit we have to find is:

$\lim _{n\to\infty}\frac{2}{5}\cdot\frac{n}{n+1}=\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}$

Note that the limit of 1/n when n tends to infinite is 0 so we get:

$\lim _{n\to\infty}\frac{2}{5}\cdot\frac{1}{1+\frac{1}{n}}=\frac{2}{5}\cdot\frac{1}{1+0}=\frac{2}{5}=0.4$

So from the test ratio r=0.4 and the series converges. Then the answer is the second option.

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1 year ago

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irinina [24]

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3 years ago

Read 2 more answers