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nika2105 [10]
3 years ago
15

The population of a local species of mosquitos can be found using an infinite geometric series where a1 = 740 and the common rat

io is one sixth. Write the sum in sigma notation, and calculate the sum (if possible) that will be the upper limit of this population.
Mathematics
1 answer:
ollegr [7]3 years ago
6 0
Sum = a1 + a2 + a3 + ... + an = Σan
Sum to infinity of a geometric sequence is given by S∞ = a/(1 - r); where a is the first term and r is the common ratio.
S∞ = 740/(1 - 1/6) = 740/(5/6) = 888
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Answer:

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Step-by-step explanation:

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Consider the figure:

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Given:

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fter production, a computer component is given a quality score of A, B, and C. On the average U of the components were given a q
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Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the given question some of the data is missing so, its correct question is defined in the attached file please find it.

Let

A is quality score of A

B is quality score of B

C is quality score of C

\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\

Let F is a value of the content so, the value is:

\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\

Now, we calculate the tooling value:

\to p[\frac{C}{F}]

using the baues therom:

\to p[\frac{C}{F}] =  \frac{p[C] \times p[\frac{F}{C} ]}{p[A] \times p[\frac{F}{A}] + p[B] \times p[\frac{F}{B}]+p[C] \times p[\frac{F}{C}] }  

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