All categories

3 years ago

The perimeter of kite LMNO is 80 feet. Side MN = 3x + 5 and side NO = x – 7 . What is the length of NO?

Mathematics

1 answer:

Law Incorporation [45]3 years ago

4 0

Answer:

The length of NO is $14\ ft$

Step-by-step explanation:

step 1

Find the value of x

we know that

The Kite has two pairs of equal-length adjacent (next to each other) sides.

The perimeter is equal to

$P=2[MN+NO]$

$P=80\ ft$

$80=2[MN+NO]$

$40=[MN+NO]$

substitute the values and solve for x

$40=[(3x+5)+(x-7)]$

$40=[4x-2]$

$4x=42$

$x=21\ ft$

step 2

Find the length of NO

$NO=(21-7)=14\ ft$

You might be interested in

What is the least common multiple of 26 and 39?

GuDViN [60]

Answer:

Step-by-step explanation:

Find the prime factorizations of the two numbers:

26 = 2 * 13

39 = 3 * 13

The LCM is the product of common and not common factors with the higher exponent.

LCM = 2 * 3 * 13 = 78

Answer: 78

5 0

3 years ago

If ava makes $15 in 2 hours, what is her rate of pay?

zalisa [80]

Answer:

$7.50 per hour

Step-by-step explanation:

15/2=7.5

7 0

3 years ago

Read 2 more answers

The body weight of a healthy 3 month-old colt should be about μ = 60 kg. (Source: The Merck Veterinary Manual, a standard refere

tatuchka [14]

Answer:

The null hypothesis will be $H_o : \mu = 60 \ kg$

The alternative hypothesis will be $H_a : \mu < 60$

The alternative hypothesis will be $H_a : \mu > 60$

The alternative hypothesis will be $H_a : \mu \ne 60$

left; right; both

Step-by-step explanation:

Considering question a

The body weight of the colt is $\mu = 60 \ kg$

The null hypothesis will be $H_o : \mu = 60 \ kg$

Considering question b

Given that we want to test the claim that the average weight of a wild Nevada colt is less than 60 kg , then

The alternative hypothesis will be $H_a : \mu < 60$

Considering question c

Given that we want to test the claim that the average weight of such a wild colt is greater than 60 kg , then

The alternative hypothesis will be $H_a : \mu > 60$

Considering question d

Given that we want to test the claim that the average weight of such a wild colt is different from 60 kg , then

The alternative hypothesis will be $H_a : \mu \ne 60$

Considering question e

For question b , the corresponding p-value will be on the left because the average weight is less than 60 kg

For question c , the corresponding p-value will be on the right because the average weight is more than 60 kg

For question d , the corresponding p-value will be on both because the average weight is different from 60 kg

5 0

2 years ago

Mr. Shamir employs two part-time typists, Inna and Jim, for his typing needs. Inna charges $15 an hour and can type 6 pages an h

coldgirl [10]

Answer:

The minimum cost would be 480$ when Inna works for 8 hours and Jim works for 20 hours.

Step-by-step explanation:

We are given the following information in the question:

Charges for 1 hour for Inna = $15

Number of pages typed by Inna in 1 hour = 6

Charges for 1 hour for Jim = $18

Number of pages typed by Jim in 1 hour = 8

Let x be the number of hours Inna work and let y be the number of hours Jim work.

Total cost = $15x + 18y$

We have to minimize this cost.

Then, we can write the following inequalities:

$6x + 8y \geq 208\\x \geq 8\\y \geq 8\\$

The corner points as evaluated from graph are: (8,20) and (24,8)

C(8,20) = 480$

C(24,8) = 504$

Hence, the minimum cost would be 480$ when Inna works for 8 hours and Jim works for 20 hours.

The attached image shows the graph.

3 0

3 years ago

Lashonda started to run on a treadmil, after setting it's timer for 64 minutes, The display states that she has finnished 68% of

Lynna [10]

Step-by-step explanation:

It is 64*0.32=20.48 minutes or 20.5 minutes.

6 0

2 years ago

Read 2 more answers