Answer: The flagpole is about 22.3 feet tall.
This is roughly the size of a two story building, assuming each floor is 10 feet or so.
Since this height is under 25 ft, this flagpole is in compliance with the regulation.
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Work Shown:
The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.
The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.
Use the tangent rule to connect the opposite and adjacent sides.
Solve for x.
tan(angle) = opposite/adjacent
tan(25) = (x-5.5)/36
36*tan(25) = x-5.5
x-5.5 = 36*tan(25)
x = 36*tan(25)+5.5
x = 22.28707569358
x = 22.3 ft is the approximate height of the flagpole
Make sure your calculator is in degree mode.
The height is not over 25 ft, so this flagpole meets the requirements.
Answer:
it is 27
Step-by-step explanation:
Subtract 33 from both sides
6x>3x+30-36x>3x+30−3
Simplify 3x+30-33x+30−3 to 3x+273x+27
6x>3x+276x>3x+27
Subtract 3x3x from both sides
6x-3x>276x−3x>27
Simplify 6x-3x6x−3x to 3x3x
3x>273x>27
Divide both sides by 3
3x>\frac{27}{3}x>
3x> 27
Simplify \frac{27}{3}
3
ANSWER: x>9
If you do 24.75-12.45 you get 12.30. So there you go!
Insert 3x - 7 for y in 15x - 5y = 14
15x - 5(3x - 7) = 14
15x - 15x + 35 = 14
0 = -21
There is no solution.
