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FinnZ [79.3K]
3 years ago
11

Find the interest on the loan if you borrowed $2,000 at 8% for 1 year.

Mathematics
1 answer:
kodGreya [7K]3 years ago
7 0
Future Value = Present Value*(1 + interest rate)^(# of years)

Future Value = $2,000(1+0.08)^1

Future Value = $2,000(1.08) = $2,160

To find the interest on the loan, we need to do our Future Value - Present Value.

Future Value - Present Value = $2,160 - $2,000 = $160
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If y = 7 when x = 6, find y when x= -21.
AysviL [449]

Answer:

24.5

Step-by-step explan ation:

y=7

x=6

7/6 y/-21

6y=-21x7

6y=-147

y=24.5

brainliest pls thank you!

5 0
3 years ago
A box contains 15 lbs.of books. There are 20 books in the box. How much does each book weigh?
Setler79 [48]

Answer:

0.75 lbs.

Step-by-step explanation:

Okay, this one is more simple. To find the weight of each book, You have to solve this division problem:

15/20

If you divided it the other way around, you would be saying each book weighed 1.33 pounds. That wouldn't be correct because then you would have over 20 lbs. of books, when you only have 15.

So, the answer is 0.75 pounds.

6 0
3 years ago
What's the answer to this
timofeeve [1]

Answer:

AC ≈ 17.3 , BC ≈ 5.3

Step-by-step explanation:

using the tangent ratio in right triangle ACD

tan51° = \frac{opposite}{adjacent} = \frac{AC}{AD} = \frac{AC}{14} ( multiply both sides by 14 )

14 × tan51° = AC , then

AC ≈ 17.3 ( to the nearest tenth )

using the cosine ratio in right triangle ABC

cos72° = \frac{adjacent}{hypotenuse} = \frac{BC}{AC} = \frac{BC}{17.3} ( multiply both sides by 17.3 )

17.3 × cos72° = BC , then

BC ≈ 5.3 ( to the nearest tenth )

5 0
2 years ago
3(4x+5)=33 What’s the value of x
atroni [7]

Answer:

the answer would be 20

8 0
3 years ago
Read 2 more answers
Log14/3 +log11/5-log22/15=log
Tamiku [17]

Answer:

log7

Step-by-step explanation:

when adding logs, apply the log rule: \log _a\left(x\right)+\log _a\left(y\right)=\log _a\left(xy\right)

∴  \log\left(\frac{14}{3}\right)+\log\left(\frac{11}{5}\right)=\log\left(\frac{14}{3}\cdot \frac{11}{5}\right)

when subtracting logs, apply the log rule: \log _a\left(x\right)\:-\:\log _a\left(y\right)=\log _a\left(\frac{x}{y}\right)

\log\left(\frac{14}{3}\cdot \frac{11}{5}\right)-\log\left(\frac{22}{15}\right)=\log\left(\frac{\frac{14}{3}\cdot \frac{11}{5}}{\frac{22}{15}}\right)\\\\=\log\left(7\right)

5 0
2 years ago
Read 2 more answers
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