Answer:
<h2>x = -0.2</h2>
Step-by-step explanation:
![-1(x+5)=3[x+2x-1)]\\\\\text{for}\ -1(x+5):\ \text{distribtutive property}\\\text{for}\ [x+(2x-1)]:\ \text{associative property}\\\\(-1)(x)+(-1)(5)=3[(x+2x)-1]\\-x-5=3(3x-1)\\\\\text{for}\ 3(3x-1):\ \text{distributive property}\\\\-x-5=(3)(3x)+(3)(-1)\\-x-5=9x-3\\\\\text{for the equation}:\ \text{addition property of equality}\\\\-x-5=9x-3\qquad\text{add 5 to both sides}\\-x-5+5=9x-3+5\\-x=9x+2\\\\\text{for the equation:}\ \text{subtraction property of equality}\\\\-x=9x+2\qquad\text{subtract}\ 9x\ \text{from both sides}](https://tex.z-dn.net/?f=-1%28x%2B5%29%3D3%5Bx%2B2x-1%29%5D%5C%5C%5C%5C%5Ctext%7Bfor%7D%5C%20-1%28x%2B5%29%3A%5C%20%5Ctext%7Bdistribtutive%20property%7D%5C%5C%5Ctext%7Bfor%7D%5C%20%5Bx%2B%282x-1%29%5D%3A%5C%20%5Ctext%7Bassociative%20property%7D%5C%5C%5C%5C%28-1%29%28x%29%2B%28-1%29%285%29%3D3%5B%28x%2B2x%29-1%5D%5C%5C-x-5%3D3%283x-1%29%5C%5C%5C%5C%5Ctext%7Bfor%7D%5C%203%283x-1%29%3A%5C%20%5Ctext%7Bdistributive%20property%7D%5C%5C%5C%5C-x-5%3D%283%29%283x%29%2B%283%29%28-1%29%5C%5C-x-5%3D9x-3%5C%5C%5C%5C%5Ctext%7Bfor%20the%20equation%7D%3A%5C%20%5Ctext%7Baddition%20property%20of%20equality%7D%5C%5C%5C%5C-x-5%3D9x-3%5Cqquad%5Ctext%7Badd%205%20to%20both%20sides%7D%5C%5C-x-5%2B5%3D9x-3%2B5%5C%5C-x%3D9x%2B2%5C%5C%5C%5C%5Ctext%7Bfor%20the%20equation%3A%7D%5C%20%5Ctext%7Bsubtraction%20property%20of%20equality%7D%5C%5C%5C%5C-x%3D9x%2B2%5Cqquad%5Ctext%7Bsubtract%7D%5C%209x%5C%20%5Ctext%7Bfrom%20both%20sides%7D)
The zeros of a function are the values of x that make the function be equal to zero.
When graphing a quadratic equation, the graph is a parabola, and the zeros of the function are the x-intercepts of the graph, which are the points where the graph intersects the x-axis.
So, if the zeros of this function are x = -8 and x = 2, that means the parabola crosses the x-axis at x = -8 and x = 2.
Therefore the correct option is the first one.
There are infinitely many lines that have the point (1,-3).
A line can be expressed as:
y=mx+b, where m=slope and b=y-intercept..
Our only restriction is that it passes through (1,-3) so
-3=1m+b
So as long as the sum of the slope and the y-intercept is equal to -3, that is one of the infinite number of lines that passes through (1, -3)
So we could also say b=-3-m then our infinite lines are:
y=mx-3-m, now any real value of m creates a specific line that passes through the point. ie the first few are
y=x-4, y=2x-5, y=3x-6 or even y=x√2-3-√2
