How do I find roots from a quadratic equation

1 answer:

6 0

Answer:The roots of any quadratic equation is given by: x = [-b +/- sqrt(-b^2 - 4ac)]/2a. Write down the quadratic in the form of ax^2 + bx + c = 0. If the equation is in the form y = ax^2 + bx +c, simply replace the y with 0. This is done because the roots of the equation are the values where the y axis is equal to 0.

Step-by-step explanation:

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(3)-2<br> Evaluate exponent

olga nikolaevna [1]

Answer:

$3^{-2} = \dfrac{1}{9}$

Step-by-step explanation:

Definition of negative exponent:

$a^{-n} = \dfrac{1}{a^n}$

In our case, a = 3 and -n = -2.

$3^{-2} = \dfrac{1}{3^2}$

Now we just evaluate the power in the denominator.

$3^{-2} = \dfrac{1}{3^2} = \dfrac{1}{9}$

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HELP PLEASE! I'll give you the most stars for explaining and giving the answer

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1. Because each element in the domain is matched exactly with one element I. The range.

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Plz help! i rlly need this question !

Mazyrski [523]

answer: she is right that y = 29, but step three should be addition property of equality.

work: let's see how she worked to isolate y. she started by subtracting 2y from both sides, so so far she is correct. after that, she added 84 to both sides, and again that is a correct step, but her proof is wrong, since you are adding and not subtracting 84, it's the addition property of equality. lastly, she divided 145 by and correctly got 29. so yes, she is correct.

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