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Eduardwww [97]
3 years ago
14

Evaluate the expression. * 23 – (12 + 6) + 8 Please help

Mathematics
2 answers:
Svetllana [295]3 years ago
6 0

answer is 13

Step-by-step explanation:

Using the BODMAS rule,bracket of division or multiplication, addition or subtraction.

This applies the rule:

therefore,

23- (12+6)+8 ,calculate within bracket first

=23-(18)+8

now remove the bracket,by multiply by the -1

=23-18+8

the start calculate from the left to right

=23-10

=13

therefore the answer is 13

Afina-wow [57]3 years ago
5 0

Answer:

13

Step-by-step explanation:

23-(12+6)+8

23-18+8

31-18

13

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Gekata [30.6K]
Since the sum of the angles of a triangle = 180°

Then  <span>80º + (2x + 2)º + 5xº  = 180</span>°
                          82° + (7x)° = 180°
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3 years ago
????? Anyone that can help giving 10 points
katen-ka-za [31]

Step-by-step explanation:

we know that perimeter of triangle is equals to side + side + side

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3 years ago
Write and inequality for the following statement: c is less than 6
Talja [164]

In order to solve this exercise you need to remember the following symbols in Inequalities:

1. The meaning of this symbol is "Greater than":

>

2. The meaning of this one is "Less than":

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4. And this one means "Greater than or equal to":

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Knowing the above, you can determine that the statement "c is less than 6", can be written as the following inequality:

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3 years ago
The quadratic function g(x) = ax^2 + bx + c has the complex roots (-5+9i) and (-5-9i). (you may assume that a = -1) what is the
gavmur [86]

Answer:

  • b = -10, c = -106

Step-by-step explanation:

<h3>Given</h3>

<u>Quadratic function </u>

  • g(x) = ax^2 + bx + c

with the roots:

  • (-5+9i) and (-5-9i)
<h3>To find </h3>
  • b and c if a = -1
<h3>Solution</h3>

<u>As we know the sum of the roots is -b/a and the product of the roots is c/a. Substituting values and solving for b and c:</u>

  • (-5 + 9i) + (-5 - 9i) = -b/-1
  • -10 = b
  • b = -10

And

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  • - c = 25 + 81
  • - c = 106
  • c = -106

g(x) = -x² -10x - 106

4 0
3 years ago
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